Question

这是qml文件。 “main.qml”

import QtQuick 2.2
import QtQuick.Controls 1.1
import QtQuick.Layouts 1.1

ApplicationWindow{
    visible:true
    width:640
    height:480
    id:window
    title:asTr("editor")

    signal show(string text)



    TextArea{
        text:"hello"
        onTextChanged:show(text);
    }

}

这是python代码。 “main.py”

import sys
from PyQt5.QtCore import QObject, QUrl, Qt
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQml import QQmlApplicationEngine

def show(text):
    print(text)


if __name__ == "__main__":
  app = QApplication(sys.argv)
  engine = QQmlApplicationEngine()
  engine.load('main.qml')
  win = engine.rootObjects()[0]
  win.show()
  sys.exit(app.exec_())

我想将main.qml中的信号“show”连接到main.py中的插槽“show”。我怎么能这样做？

Answer 1

首先也是最重要的：不要拨打你的信号show，show已经是QWindow的一个插槽。如果将名称更改为其他名称，则只需在python代码中连接qml中定义的信号：

QML：

import QtQuick 2.2
import QtQuick.Controls 1.1
import QtQuick.Layouts 1.1

ApplicationWindow{
    visible:true
    width:640
    height:480
    id:window
    title: "editor"

    signal textUpdated(string text)


    TextArea{
        text:"hello"
        onTextChanged: textUpdated(text);
    }

}

蟒：

import sys
from PyQt5.QtCore import QObject, QUrl, Qt
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQml import QQmlApplicationEngine

def show(text):
    print(text)


if __name__ == "__main__":
  app = QApplication(sys.argv)
  engine = QQmlApplicationEngine()
  engine.load('main.qml')
  win = engine.rootObjects()[0]
  win.textUpdated.connect(show)
  win.show()
  sys.exit(app.exec_())

Qt-如何使用python将函数连接到qml中的信号？使用QQmlApplicationEngine

1 个答案: