以下是我的sql表的一些记录： -
sno ID TimeRecorded LAT LON SPEED
111333 1 29/05/2015 11:21:37 22.202053 88.120521 14
111332 1 29/05/2015 11:21:27 22.202178 88.12017 14
111331 1 29/05/2015 11:21:17 22.202283 88.11985 16
111329 1 29/05/2015 11:20:57 22.202516 88.118911 16
111328 1 29/05/2015 11:18:57 22.203664 88.113067 14
111327 1 29/05/2015 11:18:47 22.203754 88.112594 14
111326 1 29/05/2015 11:18:37 22.203907 88.112205 14
111325 1 29/05/2015 11:18:27 22.204015 88.111831 16
111248 1 29/05/2015 10:46:37 22.206899 88.075263 0
111247 1 29/05/2015 10:46:27 22.206928 88.075294 3
111246 1 29/05/2015 10:46:17 22.206996 88.075241 0
111245 1 29/05/2015 10:46:07 22.207046 88.075256 0
111244 1 29/05/2015 10:45:57 22.20708 88.075294 0
111243 1 29/05/2015 10:45:47 22.207067 88.075225 0
111242 1 29/05/2015 10:45:37 22.207069 88.07521 0
111241 1 29/05/2015 10:45:27 22.207044 88.075202 0
111240 1 29/05/2015 10:45:17 22.207044 88.075202 0
111239 1 29/05/2015 10:45:07 22.207044 88.075202 0
111238 1 29/05/2015 10:44:57 22.207044 88.075202 0
111237 1 29/05/2015 10:44:47 22.207044 88.075202 0
111236 1 29/05/2015 10:44:37 22.207044 88.075202 0
111235 1 29/05/2015 10:44:27 22.207096 88.075202 0
111234 1 29/05/2015 10:44:17 22.207096 88.075202 0
111233 1 29/05/2015 10:44:07 22.207096 88.075202 0
111201 1 29/05/2015 10:38:47 22.207139 88.075248 0
111200 1 29/05/2015 10:38:37 22.207139 88.075248 0
111199 1 29/05/2015 10:38:27 22.207139 88.075248 0
111198 1 29/05/2015 10:38:17 22.207139 88.075248 0
111197 1 29/05/2015 10:38:07 22.207134 88.075202 0
111196 1 29/05/2015 10:37:57 22.20722 88.075149 0
111195 1 29/05/2015 10:37:47 22.20722 88.075149 0
111194 1 29/05/2015 10:37:37 22.20722 88.075149 0
111193 1 29/05/2015 10:37:27 22.20722 88.075149 0
111192 1 29/05/2015 10:37:17 22.20722 88.075149 0
111191 1 29/05/2015 10:37:07 22.207239 88.075141 0
111190 1 29/05/2015 10:36:57 22.207233 88.075141 0
111189 1 29/05/2015 10:36:47 22.207242 88.075134 0
111188 1 29/05/2015 10:36:37 22.207242 88.075126 0
111187 1 29/05/2015 10:36:27 22.207242 88.075126 0
111186 1 29/05/2015 10:36:17 22.207242 88.075126 0
111185 1 29/05/2015 10:36:07 22.207239 88.075119 0
111184 1 29/05/2015 10:35:57 22.207115 88.07505 0
111183 1 29/05/2015 10:35:47 22.207115 88.07505 0
111182 1 29/05/2015 10:35:37 22.207115 88.07505 0
111181 1 29/05/2015 10:35:27 22.207115 88.07505 0
111180 1 29/05/2015 10:35:17 22.207115 88.07505 0
111179 1 29/05/2015 10:35:07 22.207115 88.07505 0
111178 1 29/05/2015 10:34:57 22.207115 88.07505 0
111177 1 29/05/2015 10:34:47 22.207115 88.07505 0
111176 1 29/05/2015 10:34:37 22.207115 88.07505 0
111175 1 29/05/2015 10:34:27 22.207115 88.07505 0
我想在ID的基础上以秒为单位计算停工时间 从时间到时间之间的速度= 0，如： -
1- From '2015-05-29 10:56:17.000' to'2015-05-29 10:59:17.000' --160 seconds
2-From '2015-05-29 10:31:17.000'to'2015-05-29 10:47:17.000'--960 seconds
3-From '2015-05-29 10:31:17.000' to'2015-05-29 10:47:17.000'--1380 seconds
and so on....
如何以秒或分钟计算日期差异?????
答案 0 :(得分：0)
如果您可以使用ID，那么您只需减去前0速度的ID与序列中最后0速度的ID之间的差异。
select (select TimeRecorded from Tablename where sno = 111286) - (select TimeRecorded from Table where sno = 111246)
要显示分钟和秒数，您可以在几秒钟内完成：
select DATEPART(mi,(select TimeRecorded from tablename where sno = 111286) - (select TimeRecorded from
tablename where sno = 111246))*60
+ DATEPART(ss,(select TimeRecorded from tablename where sno = 111286) - (select TimeRecorded from
tablename where sno = 111246))
SELECT
(
(
select DATEDIFF(DD,(select TimeRecorded from tablename where sno = 111246),
(select TimeRecorded from tablename where sno = 111286))*86400
)
+
(
select DATEDIFF(HH,(select TimeRecorded from tablename where sno = 111246),
(select TimeRecorded from tablename where sno = 111286))*3600
)
+
(
select DATEDIFF(MI,(select TimeRecorded from tablename where sno = 111246),
(select TimeRecorded from tablename where sno = 111286))*60
)
+
(
select DATEDIFF(SS,(select TimeRecorded from tablename where sno = 111246),
(select TimeRecorded from tablename where sno = 111286))
)
)