仅在其当前未运行时启动应用

Question

我向用户发送推送通知，点击它时会打开应用。

我的问题是，当应用程序已经打开时，点击通知会再次启动应用程序。

我只希望它启动应用程序，如果它尚未运行。

我在通知中使用Pending Intent：

PendingIntent contentIntent = PendingIntent.getActivity(this, 0, new Intent(this, Splash.class), 0);

我看到帖子说使用：

<activity 
android:name=".Splash"
android:launchMode="singleTask"

但问题是我的正在运行的应用程序正在运行其他活动，然后在应用程序启动后7秒内完成启动，因此当应用程序运行时，Splash不是当前活动

Answer 1

为您的应用使用“启动Intent”，如下所示：

PackageManager pm = getPackageManager();
Intent launchIntent = pm.getLaunchIntentForPackage("your.package.name");
PendingIntent contentIntent = PendingIntent.getActivity(this, 0, launchIntent, 0);

将“your.package.name”替换为Android清单中包的名称。

此外，您应该从清单中删除特殊launchMode="singleTask"。标准的Android行为会做你想要的。

Answer 2

String appPackageName = "";

private void isApplicationInForeground() throws Exception {
    ActivityManager am = (ActivityManager) getSystemService(ACTIVITY_SERVICE);
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
        final List<ActivityManager.RunningAppProcessInfo> processInfos = am
                .getRunningAppProcesses();
        ActivityManager.RunningAppProcessInfo processInfo = processInfos
                .get(0);
        // for (ActivityManager.RunningAppProcessInfo processInfo : processInfos) {
        if (processInfo.importance == ActivityManager.RunningAppProcessInfo.IMPORTANCE_FOREGROUND) {
            // getting process at 0th index means our application is on top on all apps or currently open 
            appPackageName = (Arrays.asList(processInfo.pkgList).get(0));
        }
        // }
    }
    else {
        List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(1);
        ComponentName componentInfo = null;
        componentInfo = taskInfo.get(0).topActivity;
        appPackageName = componentInfo.getPackageName();
    }
}

private void notifyMessage(String text) {
    if (appPackageName.contains("com.example.test")) {
        // do not notify
    }
    else {          
        // create notification and notify user  
    }
}

Answer 3

对于那些使用 Xamarin.Android 的人。 Xamarin版 David Wasser 的答案如下：

        //Create notification
        var notificationManager = GetSystemService(Context.NotificationService) as NotificationManager;
        Intent uiIntent = PackageManager.GetLaunchIntentForPackage("com.company.app");

        //Create the notification
        var notification = new Notification(Android.Resource.Drawable.SymActionEmail, title);

        //Auto-cancel will remove the notification once the user touches it
        notification.Flags = NotificationFlags.AutoCancel;

        //Set the notification info
        //we use the pending intent, passing our ui intent over, which will get called
        //when the notification is tapped.
        notification.SetLatestEventInfo(this, title, desc, PendingIntent.GetActivity(this, 0, uiIntent, PendingIntentFlags.OneShot));

        //Show the notification
        notificationManager.Notify(0, notification);

Answer 4

不要在通知点击时显示Splash活动，而是显示您的MainActivity，因为您的启动活动将在一段时间后关闭，但MainActivity将保持打开状态

<activity 
android:name=".MainActivity"
android:launchMode="singleTask"

Answer 5

使用Splash作为片段而不是Activity。保持Splash片段（7秒），将其替换为所需的片段（着陆页）。

将launchMode =“singleTask”添加到清单。

正如Rahul已经说明的那样，如果应用程序已在运行onNewIntent()

，则会调用onCreate()

@Override
protected void onNewIntent(Intent intent) 
{   
    super.onNewIntent(intent);
}

OR

使用David的答案，似乎很有希望。

Answer 6

当点击通知并且您的代码重定向到您想要的屏幕时，只需通过调用此方法替换该代码并重定向到＆＃34; true / false＆＃34;结果基础。

    private boolean isAppOnForeground(Context context) {
    ActivityManager activityManager = (ActivityManager) context.getSystemService(Context.ACTIVITY_SERVICE);
    List<RunningAppProcessInfo> appProcesses = activityManager.getRunningAppProcesses();
    if (appProcesses == null) {
      return false;
    }
    final String packageName = context.getPackageName();
    for (RunningAppProcessInfo appProcess : appProcesses) {
      if (appProcess.importance == RunningAppProcessInfo.IMPORTANCE_FOREGROUND && appProcess.processName.equals(packageName)) {
        return true;
      }
    }
    return false;
  }

Answer 7

Intent.FLAG_ACTIVITY_BROUGHT_TO_FRONT

也许不要启动Splash Activity并重新打开（带到前面）MainActivity并用一个监听器更新UI，告诉你，你有一个新的通知（带有一个标志 - 布尔值或带有一个接口来制作听众）。

Answer 8

您可以使用有序广播来完成此任务。

1）将PendingIntent更改为开始BroadcastReceiver，这将决定是开始活动还是不做任何事情：

PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, new Intent(this, DecisionReceiver.class), 0);

2）创建决策BroadcastReceiver：

public class DecisionReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {
        context.sendOrderedBroadcast(new Intent(MainActivity.NOTIFICATION_ACTION), null, new BroadcastReceiver() {
            @Override
            public void onReceive(Context context, Intent intent) {
                if (getResultCode() == MainActivity.IS_ALIVE) {
                    // Activity is in the foreground
                }
                else {
                    // Activity is not in the foreground
                }
            }
        }, null, 0, null, null);
    }
}

3）在你的活动中创建一个BroadcastReceiver，表示它还活着：

public static final String NOTIFICATION_ACTION = "com.mypackage.myapplication.NOTIFICATION";
public static final int IS_ALIVE = 1;
private BroadcastReceiver mAliveReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        setResultCode(IS_ALIVE);
    }
};

// Register onResume, unregister onPause
// Essentially receiver only responds if the activity is the foreground activity
@Override
protected void onResume() {
    super.onResume();
    registerReceiver(mAliveReceiver, new IntentFilter(NOTIFICATION_ACTION));
}

@Override
protected void onPause() {
    super.onPause();
    unregisterReceiver(mAliveReceiver);
}

Answer 9

notificationIntent.addFlags（Intent.FLAG_ACTIVITY_SINGLE_TOP | Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK）;

[RequiredIf]

Answer 10

尝试将此添加到您的意图，如果它在后台运行，则将活动置于前面

Intent intent = new Intent(this, Splash.class); intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT); PendingIntent contentIntent = PendingIntent.getActivity(this, 0, intent, 0);

Answer 11

首先在清单文件的android:taskAffinity="com.example.testp.yourPreferredName"元素中设置默认任务Application。在android:launchMode="singleTask"上维护SplashActivity。现在，由于您的SplashActivity是您的主要条目，因此请将此代码添加到onResume()，onNewIntent()和onCreate() （在第二个想法onResume（）不建议的情况下） - 按照代码中的注释

//Note these following lines of code will work like magic only if its UPVOTED.
//so upvote before you try it.-or it will crash with SecurityException
ActivityManager am = (ActivityManager) this.getSystemService(ACTIVITY_SERVICE);

List< ActivityManager.RunningTaskInfo > taskInfo = am.getRunningTasks(1000);    
    for(int i =0; i< taskInfo.size(); i++){
        String PackageName = taskInfo.get(i).baseActivity.getPackageName();
        if(PackageName.equals("packagename.appname")){// suppose stackoverflow.answerer.Elltz
            //if the current runing actiivity is not the splash activity. it will be 1
            //only if this is the first time your <taskAffinity> is be called as a task
            if(taskInfo.get(i).numActivities >1){
                //other activities are running, so kill this splash dead!! reload!!                 
                finish();
                // i am dying in onCreate..(the user didnt see nothing, that's the good part)
                //about this code. its a silent assassin
            }
            //Operation kill the Splash is done so retreat to base.
            break;
        }
    }

此代码不适用于api 21+;要使其工作，您需要使用AppTask，这将为您节省额外的代码行，因为您不会在循环中找到Task。

希望有所帮助