Question

我有以下代码，它是地址簿（词典列表）和列表。我们的想法是按照列表的顺序打印字典中的项目（因为dicts搞乱了所有内容的顺序）。当我运行此代码时，它会抛出异常（如下所示）。我不知道自己做错了什么，因为我尝试了很多不同的变化，我不断回过头来想知道它为什么不起作用。

请帮帮忙？

addressBook = [
    {
    'Nickname': 'Jimmy',
    'Name': 'James Roberts',
    'Address': '2/50 Robe Street',
    'Phone': '0273503342'
    },
    {
    'Nickname': 'Bob',
    'Name': 'Robert',
    'Address': '1 Vivan Street',
    'Phone': '067578930'
    }
]

addressFields = ['Nickname', 'Name', 'Address', 'Phone']

def listAll(addressBook, addressFields):
    for i in addressBook:
        for key in addressFields:
            print("{0} {1}".format(key, addressBook[i][key]))

    print("{0} {1}".format(key, addressBook[i][key]))


TypeError: list indices must be integers, not dict

Answer 1

首先，在'之后，您在addressBook字面值中遗漏了'James Roberts。其次，问题是您正在执行addressBook[i][key]而不是i[key]。 i已经引用了addressBook中包含的字典，因此您的代码尝试使用list的元素作为自身的索引。

def listAll(addressBook, addressFields):
    for i in addressBook:
        for key in addressFields:
            print('{} {}'.format(key, i[key]))

Python 3友好的单行：

def listAll(addressBook, addressFields):
    print(*('{} {}'.format(j, i[j]) for i in addressBook for j in addressFields), sep='\n')

Answer 2

或者在一行中：

print('\n'.join(element for element in [j+" "+ i[j] for i in addressBook for j in addressFields]
))

Answer 3

#!/usr/bin/python

addressBook = [{'Nickname': 'Jimmy', 'Name': 'James Roberts', 'Address': '2/50 Robe Street', 'Phone': '0273503342'},{'Nickname': 'Bob', 'Name': 'Robert', 'Address': '1 Vivan Street', 'Phone': '067578930'}]

addressFields = ['Nickname', 'Name', 'Address', 'Phone']

def listAll(addressBook, addressFields):
  for i in addressBook:
    for val in addressFields:
      print("{0} {1}".format(val, i[val]))

listAll(addressBook, addressFields)

Answer 4

发布此问题后，我找到了答案。

我将addressBook for循环转换为范围（len（addressBook））并且它有效。

for i in range(len(addressBook)):

用列表顺序打印dictornary

4 个答案: