Question

这是我在C ++中学习的数组。有什么方法可以进一步简化这个吗？

cout＆lt;＆lt; ＆＃34;整数值数组＆＃34; ＆LT;＆LT; ENDL; cout＆lt;＆lt; ＆＃34; =======================＆＃34; ＆LT;＆LT; ENDL;

    int value[5] = { 17, 34, 51, 68, 85 }; // Creates an integer array list that contain a series of 5 values

    for (int loop = 0; loop < 5; loop++) {
        cout << "Integer value " << loop << ": " << value[loop] << endl;
    }

    cout << endl << "Array of double values" << endl; // First endl creates a blank line
    cout << "=======================" << endl;

    double numbers[10] = { 12.1, 24.2, 36.3, 48.4, 60.5, 72.6, 84.7, 96.8, 212.9, 3.0 }; // Creates an double integer array list that contains a series of 10 values

    for (int loop = 0; loop < 10; loop++) { // Loops array
        // Adding example " numbers[loop] = 77; " would set every number to 77

        cout << "Element at index " << loop << ": " << numbers[loop] << endl;
    }

    cout << endl << "Initializing with zero values" << endl; // First endl creates a blank line
    cout << "=======================" << endl;

    for (int loop = 0; loop < 1; loop++) { // Loops array
        // Adding " numbers[loop] = 77; " would set every number to 77
        cout << "Element at index " << loop << ": " << numbers[loop] << endl;
    }

    cout << endl << "Initializing with strings" << endl; // First endl creates a blank line
    cout << "=======================" << endl;

    // Array of strings
    string text = ( "Chair", "Table", "Plate" ) ;

    ;       for (int loop = 0; loop < 3; loop++) { // Loops array
        cout << "Element at index " << loop << ": " << text[loop] << endl;

        return 0;

Answer 1

你永远不会使用你在这里声明的数组：

int numberArray[8] = {};

这整个部分看起来像是从上面重复：

for (int loop = 0; loop < 10; loop++) { // Loops array
// Adding " numbers[loop] = 77; " would set every number to 77
cout << "Element at index " << loop << ": " << numbers[loop] << endl;

就“简化”这个问题而言，如果你使用相同数据类型的数组，你可以编写一个接受数组的函数，元素的数量，以及通过数组输出的任何你想要的循环。然后，您可以每次从main函数调用此函数，而不是重复for循环

Answer 2

也许你可以尝试这样的事情：

template <typename T>
void Printer (const vector<T> &t_elementsToPrint)
{

    // For simple value printing
    for (auto value : t_elementsToPrint)
        cout << value << "\n";

    // If you want to know the index number
    for (auto it = begin(t_elementsToPrint); it != end(t_elementsToPrint); ++it)
    {
        cout << "Element at index " << distance(begin(t_elementsToPrint), it) << " : " << *it << "\n";
    }
}

int main (int argc, char* argv[])
{

    vector<double> numbers = { 12.1, 24.2, 36.3, 48.4, 60.5, 72.6, 84.7, 96.8, 212.9, 3.0 }; // Creates an double integer array list that contains a series of 10 values

    Printer<double>(numbers);

    vector<int> numbers2 = { 17, 34, 51, 68, 85 };

    Printer<int>(numbers2);

    return 0;
}

您可以将容器从矢量更改为数组或其他可能适合您的容器，除非您确实需要原始访问权限，如果您要查找的是简单性，我建议您坚持使用STL容器。

有没有办法简化这个C ++整数循环数组？

2 个答案: