Question

我的HTML代码如下所示：

<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>

我尝试提取呈现此HTML时显示的文本。

更具体地说，对于这个例子＆＃39; a＆＃39;标签，我试图提取＆＃34; EZSTORAGE - PACK IT。存储它。 WIN - Nationwide - 限制 - 结束6/30/15＆＃34;

但我在提取全文时遇到问题，因为它被“img”分解了。标签和＆＃39; span＆＃39;。

为了提供更多背景信息，我一直在使用以下代码搜索所有＆＃39; a＆＃39;标记并提取链接文本。

for link in soup.find_all('a', id='mylink'):
    raw.append(link)
    link_text = link.contents[0].encode('utf-8')
    sweeps.append(link_text)

#output: 'EZSTORAGE - PACK IT. STORE IT. WIN - '

非常感谢任何见解！

Answer 1

使用link.text代替link.contents

，您是不是喜欢这个MWE？

text = """
<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>
"""
from bs4 import BeautifulSoup

soup = BeautifulSoup(text)

for link in soup.find_all('a', id='mylink'):
    link_text = link.text
    print link_text

结果：

EZSTORAGE - PACK IT. STORE IT. WIN -  Nationwide - Restrictions - Ends 6/30/15

Answer 2

您可以使用常规查找所有文字

import urllib,urllib2,re

content=r'<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>''



links=re.findall(r'>(.*?)<',content)
a=""
for link in links:
    a=a+link
print a

返回“EZSTORAGE - PACK IT。STORE IT.WIN - Nationwide - 限制 - 2015年6月30日结束”

使用Python中的BeautifulSoup在链接标记之间提取文本

2 个答案: