Question

gcc 4.7.2 / boost 1.58.0

我正在尝试看起来像这样的代码，几乎完全取自文档中的示例：

namespace po = boost::program_options;

po::options_description desc("Allowed options");

desc.add_options()
    ("help","produce help message")
;

po::positional_options_description pos_desc;

pos_desc.add("input-file",-1);

po::variables_map vm;

// The following line throws an std::logic_error
//  what() - error_with_option_name::m_option_style can only be one of
//           [0, allow_dash_for_short, allow_slash_for_short, allow_long_disguise
//            or allow_long]
po::store(po::command_line_parser(argc,argv).options(desc)
                                            .positional(pos_desc)
                                            .run(),
          vm);

...

当我执行应用程序时，会在注释指示的行处抛出logic_error异常：

myapp filename1

它显示了在没有（位置）参数的情况下运行时的用法。为什么在使用位置命令行参数时抛出它？

Answer 1

您需要添加＆＃34;输入文件＆＃34; desc然后pos_desc的参数，而不仅仅是后者。{这是我通常做的一个例子。

namespace po = boost::program_options;

string fin_name;

try {
  po::options_description all_opt("Options");
  all_opt.add_options()
  ("help,h", "produce help message")
  ("input,i", po::value<string>(&fin_name),
   "input files with histograms")
  ;

  po::positional_options_description pos;
  pos.add("input",-1);

  po::variables_map vm;
  po::store(po::command_line_parser(argc, argv)
    .options(all_opt).positional(pos).run(), vm);
  if (argc == 1 || vm.count("help")) {
    cout << all_opt << endl;
    return 0;
  }
  po::notify(vm);
}
catch(exception& e) {
  cerr << "\033[31mError: " <<  e.what() <<"\033[0m"<< endl;
  return 1;
}

boost :: program_options和位置参数问题

1 个答案: