Question

我正面临这个sqlite问题，我试图通过以下查询提取具有电话号码的联系人：

strerror(errno)

问题是，如果联系人的电话号码超过1个，结果将采用以下格式：

Cursor cursor = context.getContentResolver().
    query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
            new String[]{
                ContactsContract.CommonDataKinds.Phone.CONTACT_ID,
                ContactsContract.CommonDataKinds.Phone.NUMBER,
                ContactsContract.Contacts.DISPLAY_NAME,
                ContactsContract.Contacts.PHOTO_URI
            },
            ContactsContract.Contacts.HAS_PHONE_NUMBER + ">?",
            new String [] {"0"},
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC"
    );

由于数据重复而不合需要。

我想对数据库进行只有1次查询，希望可以编写这样的结果来返回结果：

id: 451, name: Maria, photoUri: null, has_phone_number: 1, phone_number: 0700 000 000
id: 451, name: Maria, photoUri: null, has_phone_number: 1, phone_number: 0800 000 000
id: 451, name: Maria, photoUri: null, has_phone_number: 1, phone_number: 0900 000 000

有可能吗？

谢谢。

Answer 1

我认为你不想做什么，这是一个使用HashMap的解决方法。它可以处理数千个条目，所以不用担心。

    Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
            new String[]{ ContactsContract.CommonDataKinds.Phone.CONTACT_ID,
                    ContactsContract.CommonDataKinds.Phone.NUMBER,
                    ContactsContract.Contacts.DISPLAY_NAME,
                    ContactsContract.Contacts.PHOTO_URI },
            ContactsContract.Contacts.HAS_PHONE_NUMBER + ">?",
            new String [] {"0"},
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

    Map<String, List<String>> phonesPerContact = new HashMap<>();
    if (cursor.moveToFirst()) {
        do {
            String name = cursor.getString(2);
            String phone = cursor.getString(1);

            if (!phonesPerContact.containsKey(name)){
                phonesPerContact.put(name, new ArrayList<String>());
            }

            phonesPerContact.get(name).add(phone);
        } while (cursor.moveToNext());
    }

    for (String name: phonesPerContact.keySet()){
        //Do whatever you want with the contact and its list of phones

        List<String> phones = phonesPerContact.get(name);
        Log.i("test", "Name: " + name + ", Numbers: " + phones.toString());
    }

sqlite android提取联系人与电话号码

1 个答案: