我前段时间决定将我自己的扫雷车版本作为一些练习编写，我就这样做了。游戏运行完美，但在决定添加“选择难度”选项后，窗口冻结，我收到一条错误消息，说该程序没有响应。还会显示 0xC0000005 行。我尝试了很多很多东西：将代码从 main（）转移到单独的函数（现在全部在int playGame（）中），在堆中分配更多内存，甚至创建一个单独的.c文件来存储一些代码，但没有任何工作。几个星期后我回到了代码中，但我仍然不知道为什么会发生这种情况。 谁能帮我这个？我希望我的代码不难阅读。我添加了一些解释什么是什么的评论。我还是C的新手。
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include "difLvl.c"
int displayFiled(char **field); //prints out the map of the field
int combine(char answer, int answer1); //combines user input and field numeration
int Randomizer(int **mineArray); //generates random mine map
int difficulty();
int playGame();
int main(){
int playGame();
playGame();
system("PAUSE");
return 0;
}
int Randomizer(int **mineArray){
int difficulty();
int i, j;
srand(time(NULL));
int mines;
int placeMine;
int totalMines;
//int difLvl=2;
int difLvl=difficulty();
for(i=0, totalMines=0; i<10; i++){
for(j=0, mines=0; j<10 && mines<difLvl; j++){
placeMine= rand() % 2;
mineArray[i][j] = placeMine;
if(placeMine==1){
++mines;
};
};
totalMines+=mines;
};
return totalMines;
}
int displayFiled(char **field){
int i, j;
printf(" A B C D E F G H I J\n");
printf(" --------------------\n");
for (i=0; i<10; i++){
if (i==9){
printf("%d |", i+1);
}else{
printf("%d |", i+1);
};
for (j=0; j<10; j++){
printf("%c ", field[i][j]);
if (j==9){
printf("\n");
};
};
};
printf("\n");
return 0;
}
int playGame(){
int displayFiled(char **field);
int combine(char answer, int answer1);
int Randomizer(int ** mineArray);
char Y_char; //column as character (a, b, c etc.)
int X; //row
int Y; //Y_char converted to a number
int **mineArray; //stores the map of mines
char **fieldDisplay; //prints out the map of the field
int i, j; //counters
int life=1;
int movePl=0; //no dying on the first move
int globalMines; //number of mines placed
int openedFields=0; //counts the number of fields opened
//int difLvl;
//int difficulty();
//difLvl= difficulty();
/*disabled the trhee lines above while I was trying some solutions*/
/*int difficulty() is now called from int Randomizer()*/
system("cls");
/*Allocates memory to mineArray*/
mineArray= (int*)calloc(10, sizeof(int));
for(i = 0; i < 10; i++){
mineArray[i] = calloc(10, sizeof(int));
};
/*Allocates memory to fieldDisplay*/
fieldDisplay= (int*)calloc(10, sizeof(int));
for(i = 0; i < 10; i++){
fieldDisplay[i] = calloc(10, sizeof(int));
};
/*default look of fields with ?*/
for (i=0; i<10; i++){
for (j=0; j<10; j++){
fieldDisplay[i][j]='?';
};
};
globalMines= Randomizer(mineArray);
while(life==1 && openedFields<(100-globalMines)){
/*for checking purposes only*/
/*for (i=0; i<10; i++){
for (j=0; j<10; j++){
printf("%d ", mineArray[i][j]);
if (j==9){
printf("\n");
};
};
};*/
//printf("\nDifficulty level %d\n", difLvl);
printf("Total number of mines is %d\n\n", globalMines);
printf("\tMove nr. %d\n\n", movePl+1);
displayFiled(fieldDisplay);
printf("Which field do You want to activate?\nType first the letter, space and then the number (A 1, B 10 etc.)\n");
scanf("%c %d", &Y_char, &X);
if (Y_char >= 'A' && Y_char <= 'Z'){
Y = Y_char - 'A';
}else if(Y_char >= 'a' && Y_char <= 'z'){
Y = Y_char - 'a';
};
/*checks if a field is a mine*/
/*X-1 because the player chooses from 1 to 10*/
if (mineArray[X-1][Y]==0 && fieldDisplay[X-1][Y]=='?'){
movePl++;
fieldDisplay[X-1][Y]='0';
openedFields=openedFields+1;
OPEN : if (((X-2)<10) && ((X-2)>=0)){
if (mineArray[X-2][Y]==0 && fieldDisplay[X-2][Y]=='?'){
fieldDisplay[X-2][Y]='0';
openedFields=openedFields+1;
};
};
if ((X<10) && (X>=0)){
if (mineArray[X][Y]==0 && fieldDisplay[X][Y]=='?'){
fieldDisplay[X][Y]='0';
openedFields=openedFields+1;
};
};
if (((Y+1)<10) && ((Y+1)>=0)){
if (mineArray[X-1][Y+1]==0 && fieldDisplay[X-1][Y+1]=='?'){
fieldDisplay[X-1][Y+1]='0';
openedFields=openedFields+1;
};
};
if (((Y-1)<10) && ((Y-1)>=0)){
if (mineArray[X-1][Y-1]==0 && fieldDisplay[X-1][Y-1]=='?'){
fieldDisplay[X-1][Y-1]='0';
openedFields=openedFields+1;
};
};
system("cls"); //clears console screen
}else if (mineArray[X-1][Y]==0 && fieldDisplay[X-1][Y]=='0'){
system("cls");
printf("You can't choose an already opened field!\n\n");
}else if(mineArray[X-1][Y]==1 && movePl==0){
/*only activates on the first turn if players hits mine*/
movePl++;
mineArray[X-1][Y]= 0;
fieldDisplay[X-1][Y]='0';
globalMines=globalMines-1;
goto OPEN;
system("cls");
}else{
system("cls");
printf("YOU DIED ! YOU DIED ! YOU DIED !\n\n");
printf("Moves successfully made: %d\n\n", movePl-1);
fieldDisplay[X-1][Y]='1';
displayFiled(fieldDisplay);
--life;
};
};
if(openedFields==(100-globalMines)){
printf("Congratulations! You won the game!\n\n");
displayFiled(fieldDisplay);
};
for(i = 0; i < 10; i++){
free(mineArray[i]);
};
free(mineArray);
for(i = 0; i < 10; i++){
free(fieldDisplay[i]);
};
free(fieldDisplay);
return 0;
}
difLvl.c文件：
#include <stdio.h>
#include <stdlib.h>
int difficulty(){
int difLvl;
while(1){
printf("Please choose a difficulty level:\n");
printf("Easy-1\nNormal-2\nNightmare-3\n");
printf("Your answer: ");
scanf(" %d", &difLvl);
if(difLvl>=1 && difLvl<=3){
break;
}else{
system("cls");
continue;
};
};
system("cls");
return difLvl;
}
我创建了它，因为我认为可能 main（）中有太多代码，这可能就是为什么难度选项无法正常工作。
EDIT 在提示用户输入难度级别后，将创建地雷图，但在选择字段后，程序会崩溃。
解决 scanf（“％c％d”，＆amp; Y_char，＆amp; X）; 变成 scanf（“％c％d”，＆amp; Y_char，＆amp; X）;
答案 0 :(得分：3)
首先，您没有正确分配二维字段。 “外部”字段必须包含int *，而不仅仅是int：
mineArray = calloc(10, sizeof(*mineArray));
for (i = 0; i < 10; i++) {
mineArray[i] = calloc(10, sizeof(*mineArray[i]));
}
分段错误的另一个潜在来源是Y可能最终未初始化，因此具有垃圾值。原因是scanf：
scanf("%c %d", &Y_char, &X);
大多数scanf格式会在转化前跳过空格，但%c则不会。当您希望阅读一封信时，很有可能将新行字符作为%c的字符读取。因为新行字符是空白字符，您可以通过在%c之前放置空格来进行热修复？格式：
scanf(" %c %d", &Y_char, &X);
（我说热修复，因为它不是一个好的解决方案。scanf不会特别处理换行符;它们只是空格。更好的解决方案可能是首先读取一行fgets，然后使用sscanf进行扫描。至少可以将每一行视为frash输入。（您的输入确实应该确保忽略错误的输入。）
最后，包含*.c文件很奇怪。如果你想在各种文件上传播ypur项目，这基本上是一个好主意，你应该为每个*.c编写一个头文件，它有文件的接口。将头文件包含在其他*.c个文件中;将*.c文件分别编译为对象，然后链接它们。此过程通常由Makefile或项目控制。