Question

我尝试将数据插入“studentremark”表。它有一个TEXT数据类型的字段。但是当我将数据插入该字段时，内容显示为“未定义”。这是代码“我正在使用ajax进行页面处理。

$faculty=$_REQUEST['faculty'];
$stcode=$_REQUEST['stcode'];
$rem=$_REQUEST['rem'];
$date = date('Y-m-d');
$sql = "INSERT INTO studentremark (STCODE, TID, rdate, remarks) VALUES (?, ?, ?, ?)";
$query = $mysqli->prepare($sql);
$query->bind_param('siss',$stcode, $faculty, $date, $rem);
if(!$query->execute())
{
    echo("Some unknown error occurs, Item cannot be added.");
}
else
{
    echo("Student remarks added successfully !!");
}

请帮忙。提前谢谢。

Answer 1

试试这个：

    $sql = "INSERT INTO studentremark (STCODE, TID, rdate, remarks) VALUES (?, ?, ?, ?)";
    $query = $mysqli->prepare($sql);
    $query->bind_param('siss',$stcode, $faculty, $date, $rem);

    $faculty=$_REQUEST['faculty'];
    $stcode=$_REQUEST['stcode'];
    $rem=$_REQUEST['rem'];
    $date = date('Y-m-d');

    if(!$query->execute()) {
        echo("Some unknown error occurs, Item cannot be added.");
    } else {
        echo("Student remarks added successfully !!");
    }

查看此php manual了解详情。

Answer 2

查看您的代码，您有四个占位符，但尝试绑定五个值，修复它，尝试使用下面的代码

    $sql = "INSERT INTO studentremark (STCODE, TID, rdate, remarks) VALUES (?, ?, ?, ?)";
    $query = $mysqli->prepare($sql);
    $query->bind_param('siss',$stcode, $date, $rem); // looking at columns i felt $faculty was extra so i removed it.

然后，要查看确切的错误消息，请使用以下过程执行查询

$query->execute() or die(mysqli_error());

当我们尝试添加数据时，MySqli中的TEXT字段显示“未定义”

2 个答案: