Question

使用这样的例子我想计算条目数。并在“文本”字段中表示具有条目数的字符串。比如，例如：

1: number of entries(1)
21: number of entries(2)
...

我应该把我的计数器变量放在哪里？

import random
from tkinter import *

class MyApp(Frame):

    def __init__(self, master):
        super(MyApp, self).__init__(master)
        self.grid()
        self.create_widgets()        

    def create_widgets(self):

        Label(self, text = 'Your number:').grid(row = 0, column = 0, sticky = W)
        self.num_ent = Entry(self)
        self.num_ent.grid(row = 0, column = 1, sticky = W)
        Button(self, text = 'Check', command = self.update).grid(row = 0, column = 2, sticky = W)
        self.user_text = Text(self, width = 50, height = 40, wrap = WORD)
        self.user_text.grid(row = 2, column = 0, columnspan = 3)

    def update(self):

        guess = self.num_ent.get()
        guess += '\n'
        self.user_text.insert(0.0, guess)

root = Tk()
root.geometry('410x200')
root.title('Entries counter')
app = MyApp(root)
root.mainloop()

Answer 1

看来你正在使用Python 3。

存储计数器的最简单方法是使用dictionary。关键是您正在计算的文本（根据您的示例为1和21），该值存储计数本身（例如1和2）。

您示例的结构化数据如下所示：

{
  '1':  1,
  '21': 2
}

最后的代码：

from tkinter import *

class MyApp(Frame):
  def __init__(self, master):
    super(MyApp, self).__init__(master)

    #this is your counter variable
    self.entries = {}

    self.grid()
    self.create_widgets()        

  def create_widgets(self):
    Label(self, text = 'Your number:').grid(row = 0, column = 0, sticky = W)
    self.num_ent = Entry(self)
    self.num_ent.grid(row = 0, column = 1, sticky = W)
    Button(self, text = 'Check', command = self.update).grid(row = 0, column = 2, sticky = W)
    self.user_text = Text(self, width = 50, height = 40, wrap = WORD)
    self.user_text.grid(row = 2, column = 0, columnspan = 3)

  def update(self):
    #get the new entry from the text field and strip whitespaces
    new_entry = self.num_ent.get().strip()

    #check if the entry is already in the counter variable
    if new_entry in self.entries:
      #if it is: increment the counter
      self.entries[new_entry] += 1
    else:
      #if it's not: add it and set its counter to 1
      self.entries[new_entry] = 1

    #delete the whole text area
    self.user_text.delete('0.0', END)

    #get every entry from the counter variable, sorted alphabetically
    for key in sorted(self.entries):
      #insert the entry at the end of the text area
      self.user_text.insert(END, '{}: number of entries({})\n'.format(key, self.entries[key]))

root = Tk()
root.geometry('410x200')
root.title('Entries counter')
app = MyApp(root)
root.mainloop()

Answer 2

如果我理解你想要的东西，只需记下按钮数量，你可以在__init__中定义一个计数变量，如

self.count = 0

并在update中增加并打印

def update(self):
    self.count += 1
    guess = self.num_ent.get()
    guess += '\n'
    self.user_text.insert(0.0, 'Guess #{}: {}'.format(self.count, guess))

如何在str中保存条目的计数器并在文本字段中显示？

2 个答案: