Question

我有一张表QuotesTable - 主键是quotesid。

我有sql-statement：

 select * from QuotesTable where quotesid in (103,7,16,50,41,80,67,64)

这将按以下顺序返回结果：

 7
 16
 41
 .........
 103 and so on.

但我需要按照查询（103,7,16,50,41,80,67,64）中指定的顺序执行结果：

 103,
 7
 16
 .......
 64 and so on.

有没有办法实现这个？

Answer 1

试试这个：

select * from QuotesTable where quotesid in (103,7,16,50,41,80,67,64)
order by case quotesid when 103 then 1
                       when  7  then 2
                       when 16  then 3
                       when 50  then 4
                       when 41  then 5
                       when 80  then 6
                       when 67  then 7
                       when 64  then 8
         end

如果这些值增长，那么您可以在数据库中创建一个表：

create table QuotesOrderingTable(quotesid int, orderid int)
go

用适当的值填充它：

insert into QuotesOrderingTable values
(103, 1),
(7, 2),
(16, 3),
(50, 4),
(41, 5),
(80, 6),
(67, 7),
(64, 8),
(..., 9),
(..., 10),
...

然后用它来订购：

select qt.* from QuotesTable qt
join QuotesOrderingTable qot on qt.quotesid = qot.quotesid
where qt.quotesid in (103,7,16,50,41,80,67,64)
order by qot.orderid

Answer 2

另一个选择是这样做：

SELECT * FROM QuotesTable q
JOIN (SELECT 1 ordering, 103 quotesid UNION ALL
      SELECT 2         , 7 UNION ALL
      SELECT 3         , 16 UNION ALL
      SELECT 4         , 50 UNION ALL
      SELECT 5         , 41 UNION ALL
      SELECT 6         , 80 UNION ALL
      SELECT 7         , 67 UNION ALL
      SELECT 8         , 64) o ON o.quotesid = q.quotesid
ORDER BY o.ordering

不是最漂亮的，但至少你没有重复WHERE子句

另一种变化，看起来更好一点：

:nth-of-type(2)

按where子句中的指定排序查询结果

2 个答案: