Question

我在spring + mvn中启动了一个项目，然后在创建项目时，还有两个文件：SampleApplication.java和WebConfig.java，后来我在路径中创建了一个文件web.xml：

../的src /主/ web应用/ WEB-INF

PS：我确定我的档案是正确的

问题是当我执行mvn run时，它识别了SampleApplication.java和WebConfig.java，我希望它只能识别web.xml，我该怎么做？

这是我的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

  <!-- The definition of the Root Spring Container shared by all Servlets
  and Filters -->
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
      /WEB-INF/spring/root-context.xml
      /WEB-INF/spring/security.xml
      classpath:di-context.xml
    </param-value>
  </context-param>

  <!-- Creates the Spring Container shared by all Servlets and Filters -->
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>

  <!-- Processes application requests -->
  <servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

  <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>
    <filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>

</web-app>

我的WebConfig.java

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.ViewResolver;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;

import com.lyncode.jtwig.mvc.JtwigViewResolver;

@Configuration
@EnableWebMvc
@ComponentScan(basePackages="APP")
public class WebConfig extends WebMvcConfigurerAdapter {

    @Bean
    public ViewResolver viewResolver() {
        JtwigViewResolver jtwigViewResolver = new JtwigViewResolver();
        jtwigViewResolver.setPrefix("/WEB-INF/views/");
        jtwigViewResolver.setSuffix(".jsp");
        return jtwigViewResolver;
    }

}

我的SampleApplication.java

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.annotation.Import;

@Import(WebConfig.class)
@EnableAutoConfiguration
public class SampleApplication {

    public static void main(String[] args) throws Exception {
        SpringApplication.run(SampleApplication.class, args);
    }
}

如何从WebConfig.java转换为web.xml？

0 个答案: