Safari通过地理位置多次请求权限

时间:2015-05-28 14:04:49

标签: javascript safari geolocation

我一直在努力:http://davidcool.com/feeds

除了Safari之外,它在所有浏览器中都能正常工作。有时Safari会在无限循环中请求地理定位权限,有时它会像它应该的那样只询问一次,大多数情况下它会要求3次...所有其他浏览器按计划询问一次。

以下是代码:

    function success(position) {
    //output lat+long data
    //console.log(position);
    //var s = document.querySelector('#status');
    //s.innerHTML = "Latitude: " + position.coords.latitude + "<br />Longitude: " + position.coords.longitude + "<br />";
    var s = document.querySelector('#status');
    if (s.className == 'success') {
        // not sure why we're hitting this twice in FF, I think it's to do with a cached result coming back    
        return;
    }
    s.innerHTML = "success";
    s.className = 'success';

    //get timezone info
    $.ajax({
          url:'https://maps.googleapis.com/maps/api/timezone/json?location=' + position.coords.latitude + ',' + position.coords.longitude + '&timestamp=' + Math.floor(position.timestamp/1000) + '&language=en&key=????',
          dataType: "json",
          async:false,
          cache:false,
          error:
            function(res){
              console.log(res);
              },
          success:
              function(res){
                //console.log(res);
                time_zone_id = res.timeZoneId;
                time_zone_name = res.timeZoneName;
                //var t = document.querySelector('#status1');
                //t.innerHTML = "Time Zone ID: " + res.timeZoneId + "<br />Time Zone Name: " + res.timeZoneName + "<br />" ;
              }
        });
    //get address info
    $.ajax({
          url:'https://maps.googleapis.com/maps/api/geocode/json?latlng=' + position.coords.latitude + ',' + position.coords.longitude + '&language=en&key=????',
          dataType: "json",
          async:false,
          cache:false,
          error:
            function(res){
              console.log(res);
              },
          success:
              function(res){
                //console.log(res);
                city = res.results[2].address_components[1].long_name;
                address = res.results[2].formatted_address;
                //var t = document.querySelector('#status2');
                //t.innerHTML = "Address: " + res.results[0].formatted_address ;
              }
        });

    //get weather info
    $('#weather').load("weather.php", {'latitude':position.coords.latitude, 'longitude':position.coords.longitude, 'local_time_zone_id':time_zone_id, 'local_time_zone_name':time_zone_name, 'city':city, 'address':address});
};

function error(msg) {
  var s = document.querySelector('#weather');
  //s.innerHTML = typeof msg == 'string' ? msg : "Failed to get location. Try refreshing.";
  s.innerHTML = typeof msg == 'string' ? msg : "Failed to get location. Try refreshing.";
  s.className = 'fail';
};

//get lat+long info
if (navigator.geolocation) {
  navigator.geolocation.getCurrentPosition(success, error);
  //setTimeout(navigator.geolocation.getCurrentPosition(success, error), 500);
} else {
  error('not supported');
};

我看过其他人有同样的问题,但未能找到明确答案的原因。有什么想法吗?

有趣的是,在我的开发Mac上,它只会一直询问,在另一台开发Mac上它会多次询问!相同的操作系统和相同版本的Safari 8.0.6。

1 个答案:

答案 0 :(得分:0)

我真的不是100%肯定,但我遇到了同样的问题。然后,我删除了msg回调中的error参数,现在它似乎在Safari中正常工作。

所以你的error回调应该是

function error() {
    var s = document.querySelector('#weather');
    s.innerHTML = "Failed to get location";
    s.className = 'fail';
}

让我知道这是否有效!