在python

Question

我已经完成了所有主题，但仍然无法解决问题

def process(date)
    #here how to know that I need to convert date into raw literal
    date = date.replace('\\', ' ')
process("21\3\90")

输出

21 90

3被跳过

虽然在这里工作

print r'pictures\12\761_1.jpg'.replace("\\", " ")

输出

pictures 12 761_1.jpg

将21\12\1234转换为21 12 1234

的任何帮助

Answer 1

你需要在＆＃34; 3＆＃34;之前逃避反斜杠。 即使反斜杠在引号中，它也不会被转义 如果您在函数中以编程方式插入值，那么我建议您执行另一个.replace并替换＆＃34; \＆＃34;使用＆＃34; - ＆＃34;

那应该将字符串转换为＆＃34; 21-3-90＆＃34;如果你需要进一步细分，你可以替换＆＃34; - ＆＃34;到了＃34; ＆＃34;正如你原先的意图。

akhter@uf8b156e44b21553641ed:~/PycharmProjects/untitled2$ python3.2
Python 3.2.3 (default, Feb 27 2014, 21:31:18) 
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def process(date):
...     date = date.replace("\\", " ")
...     print(date)
... 
>>> process("21\\3\\90")
21 3 90
>>> process("13\\4\\90")
13 4 90
>>> 

akhter@uf8b156e44b21553641ed:~/PycharmProjects/untitled2$ python2.7
Python 2.7.3 (default, Dec 18 2014, 19:10:20) 
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def process(date):
...     date = date.replace("\\", " ")
...     print(date)
... 
>>> process("21\\3\\90")
21 3 90
>>> 
akhter@uf8b156e44b21553641ed:~/PycharmProjects/untitled2$ python3.2
Python 3.2.3 (default, Feb 27 2014, 21:31:18) 
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def process(date):
...     date = date.replace('\\', ' ')
...     print(date)
... 
>>> process("21\\3\\90")
21 3 90
>>>