Question

具有
obs1 = new Rx.Observable.interval(1000); obs2 = obs1.take(2);
在obs2发出的第二个值之后，obs1将完成怎么样obs1？
它会完成还是继续射击？

Answer 1

take运算符返回一个新的可观察序列，该序列对Rx.Observable.interval生成的源可观察序列的操作没有影响。由于Rx.Observable.interval是一个“热门”可观察对象，obs1即使在obs2完成后也会继续发出值。

var obs1 = Rx.Observable.interval(1000);
obs1.subscribe(function(x) { document.write("obs1: " + x + '<br \>'); }, null, function(x) { document.write("obs1 completed" + '<br \>'); });
var obs2 = obs1.take(2);
obs2.subscribe(function(x) { document.write("obs2: " + x + '<br \>'); }, null, function(x) { document.write("obs2 completed" + '<br \>'); });

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＆＃34;采取＆＃34; observable隐含完成？

1 个答案: