以下是我的更新查询：
UPDATE ( SELECT BTD_ITEM_CODE,
INVI_ITEM_CODe,
BTD_UOM_CODE,
INVI_UOM_CODE,
BTD_GRADE_CODE,
INVI_GRADE_CODE_1,
SUM (BTD_QTY) BTD_QTY,
SUM (INVI_QTY) INVI_QTY,
SUM (BTD_QTY_LS) BTD_QTY_LS,
SUM (INVI_QTY_LS) INVI_QTY_LS,
SUM (BTD_QTY_BU) BTD_QTY_BU,
SUM (INVI_QTY_BU) INVI_QTY_BU
FROM AA_BIN_TRANSACTIONS_DET
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_SYS_ID =
AA_BIN_TRANSACTIONS_DET.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_TXN_CODE =
OT_INVOICE_HEAD.INVH_TXN_CODE
AND AA_BIN_TRANSACTIONS_HEAD.BTH_NO =
OT_INVOICE_HEAD.INVH_NO
INNER JOIN
OT_INVOICE_ITEM
ON OT_INVOICE_ITEM.INVI_INVH_SYS_ID =
OT_INVOICE_HEAD.INVH_SYS_ID
AND AA_BIN_TRANSACTIONS_DET.BTD_ITEM_CODE =
OT_INVOICE_ITEM.INVI_ITEM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_UOM_CODE =
OT_INVOICE_ITEM.INVI_UOM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_GRADE_CODE =
OT_INVOICE_ITEM.INVI_GRADE_CODE_1
GROUP BY BTD_ITEM_CODE, BTD_UOM_CODE, BTD_GRADE_CODE)
SET INVI_QTY = BTD_QTY,
INVI_QTY_LS = BTD_QTY_LS,
INVI_QTY_BU = BTD_QTY_BU
WHERE INVI_ITEM_CODE = BTD_ITEM_CODE
AND INVI_UOM_CODE = BTD_UOM_CODE
AND INVI_GRADE_CODE_1 = BTD_GRADE_CODE;
我需要使用OT_INVOICE_ITEM中的值更新详细表AA_BIN_TRANSACTIONS_DET中的值。需要将3个值BTD_QTY，BTD_QTY_LS和BTD_QTY_BU相加，因为表中有多个事务。详细信息表中的唯一标识符为BTD_ITEM_CODE。事务代码和编号对于标头表OT_INVOICE_HEAD和AA_BIN_TRANSACTIONS_HEAD都是通用的。两个表的标题和详细表也需要连接。最后，我们从AA_BIN_TRANSACTIONS_DET获得的总和值需要更新为OT_INVOICE_ITEM。
我尝试了上面的代码，但错误ORA-01732: data manipulation operation not legal on this view。我不明白为什么。
INVI_ITEM_CODE应与BTD_ITEM_CODE匹配，INVI_UOM_CODE应与BTD_UOM_CODE匹配且INVI_GRADE_CODE_1应与BTD_GRADE_CODE匹配，则只应更新记录。< / p>
提前致谢。
答案 0 :(得分：0)
如果以下查询有帮助，请与我们联系 -
with t1 as
( SELECT BTD_ITEM_CODE,
INVI_ITEM_CODe,
BTD_UOM_CODE,
INVI_UOM_CODE,
BTD_GRADE_CODE,
INVI_GRADE_CODE_1,
SUM (BTD_QTY) BTD_QTY,
SUM (INVI_QTY) INVI_QTY,
SUM (BTD_QTY_LS) BTD_QTY_LS,
SUM (INVI_QTY_LS) INVI_QTY_LS,
SUM (BTD_QTY_BU) BTD_QTY_BU,
SUM (INVI_QTY_BU) INVI_QTY_BU
FROM AA_BIN_TRANSACTIONS_DET
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_SYS_ID =
AA_BIN_TRANSACTIONS_DET.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_TXN_CODE =
OT_INVOICE_HEAD.INVH_TXN_CODE
AND AA_BIN_TRANSACTIONS_HEAD.BTH_NO =
OT_INVOICE_HEAD.INVH_NO
INNER JOIN
OT_INVOICE_ITEM
ON OT_INVOICE_ITEM.INVI_INVH_SYS_ID =
OT_INVOICE_HEAD.INVH_SYS_ID
AND AA_BIN_TRANSACTIONS_DET.BTD_ITEM_CODE =
OT_INVOICE_ITEM.INVI_ITEM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_UOM_CODE =
OT_INVOICE_ITEM.INVI_UOM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_GRADE_CODE =
OT_INVOICE_ITEM.INVI_GRADE_CODE_1
GROUP BY BTD_ITEM_CODE,
INVI_ITEM_CODe,
BTD_UOM_CODE,
INVI_UOM_CODE,
BTD_GRADE_CODE,
INVI_GRADE_CODE_1)
Update T1
SET INVI_QTY = BTD_QTY,
INVI_QTY_LS = BTD_QTY_LS,
INVI_QTY_BU = BTD_QTY_BU
答案 1 :(得分：0)
我通过以下查询完成了它，它是一个非常长且重复的查询但是有没有优化或简短的查询来做到这一点？
UPDATE OT_INVOICE_ITEM
SET INVI_QTY =
(SELECT SUM (BTD_QTY) BTD_QTY
FROM AA_BIN_TRANSACTIONS_DET
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_SYS_ID =
AA_BIN_TRANSACTIONS_DET.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_TXN_CODE =
OT_INVOICE_HEAD.INVH_TXN_CODE
AND AA_BIN_TRANSACTIONS_HEAD.BTH_NO =
OT_INVOICE_HEAD.INVH_NO
INNER JOIN
OT_INVOICE_ITEM
ON OT_INVOICE_ITEM.INVI_INVH_SYS_ID =
OT_INVOICE_HEAD.INVH_SYS_ID
AND AA_BIN_TRANSACTIONS_DET.BTD_ITEM_CODE =
OT_INVOICE_ITEM.INVI_ITEM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_UOM_CODE =
OT_INVOICE_ITEM.INVI_UOM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_GRADE_CODE =
OT_INVOICE_ITEM.INVI_GRADE_CODE_1),
INVI_QTY_LS =
(SELECT SUM (BTD_QTY_LS) BTD_QTY_LS
FROM AA_BIN_TRANSACTIONS_DET
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_SYS_ID =
AA_BIN_TRANSACTIONS_DET.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_TXN_CODE =
OT_INVOICE_HEAD.INVH_TXN_CODE
AND AA_BIN_TRANSACTIONS_HEAD.BTH_NO =
OT_INVOICE_HEAD.INVH_NO
INNER JOIN
OT_INVOICE_ITEM
ON OT_INVOICE_ITEM.INVI_INVH_SYS_ID =
OT_INVOICE_HEAD.INVH_SYS_ID
AND AA_BIN_TRANSACTIONS_DET.BTD_ITEM_CODE =
OT_INVOICE_ITEM.INVI_ITEM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_UOM_CODE =
OT_INVOICE_ITEM.INVI_UOM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_GRADE_CODE =
OT_INVOICE_ITEM.INVI_GRADE_CODE_1),
INVI_QTY_BU =
(SELECT SUM (BTD_QTY_BU) BTD_QTY_BU
FROM AA_BIN_TRANSACTIONS_DET
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_SYS_ID =
AA_BIN_TRANSACTIONS_DET.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD
ON AA_BIN_TRANSACTIONS_HEAD.BTH_TXN_CODE =
OT_INVOICE_HEAD.INVH_TXN_CODE
AND AA_BIN_TRANSACTIONS_HEAD.BTH_NO =
OT_INVOICE_HEAD.INVH_NO
INNER JOIN
OT_INVOICE_ITEM
ON OT_INVOICE_ITEM.INVI_INVH_SYS_ID =
OT_INVOICE_HEAD.INVH_SYS_ID
AND AA_BIN_TRANSACTIONS_DET.BTD_ITEM_CODE =
OT_INVOICE_ITEM.INVI_ITEM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_UOM_CODE =
OT_INVOICE_ITEM.INVI_UOM_CODE
AND AA_BIN_TRANSACTIONS_DET.BTD_GRADE_CODE =
OT_INVOICE_ITEM.INVI_GRADE_CODE_1)
答案 2 :(得分：0)
请尝试这个
Update OT_INVOICE_ITEM Z
SET ( INVI_QTY, INVI_QTY_LS, INVI_QTY_BU ) = (
WITH T1 as (
SELECT BTD_ITEM_CODE, BTD_UOM_CODE, BTD_GRADE_CODE, INVH_SYS_ID,
SUM (BTD_QTY) BTD_QTY,
SUM (BTD_QTY_LS) BTD_QTY_LS,
SUM (BTD_QTY_BU) BTD_QTY_BU,
FROM AA_BIN_TRANSACTIONS_DET A
INNER JOIN
AA_BIN_TRANSACTIONS_HEAD B
ON B.BTH_SYS_ID = A.BTD_BTH_SYS_ID
INNER JOIN
OT_INVOICE_HEAD C
ON B.BTH_TXN_CODE = C.INVH_TXN_CODE
AND B.BTH_NO = C.INVH_NO
Group by BTD_ITEM_CODE, BTD_UOM_CODE, BTD_GRADE_CODE, INVH_SYS_ID
)
SELECT BTD_QTY, BTD_QTY_LS,
BTD_QTY_BU
FROM T1
WHERE (BTD_ITEM_CODE, BTD_UOM_CODE, BTD_GRADE_CODE, INVH_SYS_ID) =
(Z.INVI_ITEM_CODE, Z.INVI_UOM_CODE, Z.INVI_GRADE_CODE_1, Z.INVI_INVH_SYS_ID)
and exists
( Select 1
From t1
WHERE (BTD_ITEM_CODE, BTD_UOM_CODE, BTD_GRADE_CODE, INVH_SYS_ID) =
(Z.INVI_ITEM_CODE, Z.INVI_UOM_CODE, Z.INVI_GRADE_CODE_1, Z.INVI_INVH_SYS_ID)
)
)