Swift 1.2添加参数到URL不起作用。早期工作完美

Question

我已将我的XCode更新为6.3.2并且我正在向URL添加参数但是“+”运算符不起作用并且给我和下面的错误

这是我在其中添加strEmail（NSString对象）作为参数的URL。

var urlstring = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail=" + strEmail

这是我得到的错误。

"Binary Operator '+' cannot be applied to operands of type 'String' and 'NSString' "

Answer 1

您可以使用字符串插值

var urlstring = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail=\(strEmail)"

或将strEmail强制转换为String

var urlstring  = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail=" + (strEmail as String)

Answer 2

从Swift 1.2开始，NSString到String的隐式转换已被删除：

来自the release notes：

  

已删除从桥接的Objective-C类（NSString / NSArray / NSDictionary）到其对应的Swift值类型（String / Array / Dictionary）的隐式转换，使Swift类型系统更简单，更可预测。

您必须使用String {<1}}将其明确转换为as：

"...iverEmail=" + (strEmail as String)

Answer 3

您需要将NSString转换为String类型。有不同的方法，见下文：

var urlstring = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail=" + String(strEmail)

或

var urlstring = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail="
+ (strEmail as String)

或

var urlstring = "http://example.com/api/api.php?action=getReceivedMessages&ReceiverEmail=\(strEmail)"