注意：回显数组时，数组到字符串转换

Question

IM收到错误

Notice: Array to string conversion php

通过从外部类调用我的数组..任何人都可以在这里发现问题

脚本home.php

echo b::addarray(123, sea, 1);//i tried this way,dint work either("123","sea","1")
die();

带有数组的脚本

class b
{

    static function addarray($a,$b,$c){

        $red = array();
        array_push($red, $a,$b,$c);
        return $red;
    }
}

Answer 1

按照以下方式尝试，因为您需要回复array print_r()或var_dump()

$re = new b();
$result = $re::addarray(123,'sea',1);
print_r($result);

Answer 2

sea是一个字符串，应该引用它。试试这个

 <?php
        class b
    {

        static function addarray($a,$b,$c){

           static  $red = array();
            array_push($red, $a,$b,$c);
            return $red;
        }
        }


      print_r(b::addarray(123, "sea", 1));
    ?>

Answer 3

print_r(b::addarray(123, sea, 1));

  or

foreach(b::addarray(123, sea, 1) as $key=>$val) {

   echo $key."#".$val;

}