Question

我正在努力选择至少拥有其中一个城市的国家/地区。另一个（提供）列表中的名称。很抱歉很难解释，请参阅下面的代码：

当我调用GetListOfCountires时，它应该返回NZ和CN。我也想用Linq而不是foreach。

    private static List<Country> Countries = new List<Country>(); 
    private static void Main()
    {
        var city1 = new City {Name = "Auckland"};
        var city2 = new City { Name = "Wellington" };
        var city3 = new City { Name = "Perth" };
        var city4 = new City { Name = "Sydney" };
        var city5 = new City { Name = "Beijing" };
        var country1 = new Country {Name = "NZ", Cities = new List<City> {city1, city2}};
        var country2 = new Country { Name = "AU", Cities = new List<City> { city3, city4 } };
        var country3 = new Country { Name = "CN", Cities = new List<City> { city5 } };
        Countries.Add(country1);
        Countries.Add(country2);
        Countries.Add(country3);
        List<String> cityNames = new List<string>{"Auckland", "Beijing"};
        var countries = GetListOfCountires(cityNames); // this should return NZ, and CN
    }

    public class Country
    {
        public string Name;
        public List<City> Cities = new List<City>();
    }

    public class City
    {
        public string Name;
    }

    public static List<Country> GetListOfCountires(List<String> cityNames)
    {
        List<Country> result = new List<Country>();
        foreach (var cityName in cityNames)
        {
            result.Add(Countries.Where(x=>x.Cities.Contains(cityName))); // error???
        }
        return result;
    }

谢谢

Answer 1

在您的城市名称列表和每个国家/地区的城市列表之间执行交集，只返回存在此类交叉点的国家/地区。

var countries = Countries.Where(x => x.Cities.Intersect(cityNames).Any());

Answer 2

您需要做什么才能让Any列表中cityNames列出的public static List<Country> GetListOfCountires(List<String> cityNames) { return Countries .Where(country => country.Cities.Any(city => cityNames.Contains(city.Name)) .ToList() }个国家/地区

services.factory('errorInterceptor', ['$injector','$location', function ($injector, $location, $q, $state) {
return {
    'responseError': function (rejection) {
        $injector.get('$state').transitionTo('404');
        return $q.reject(rejection);

    }
  };
}]);

services.config(function ($httpProvider) {
    $httpProvider.interceptors.push('errorInterceptor');
});

Linq查询 - 在另一个列表中列出

2 个答案: