这是我的代码,它采用“1,5,0,4”或“1.5.0.4”形式的两个版本标识符,并确定哪个是较新的版本。
请提出建议或改进!
/// <summary>
/// Compares two specified version strings and returns an integer that
/// indicates their relationship to one another in the sort order.
/// </summary>
/// <param name="strA">the first version</param>
/// <param name="strB">the second version</param>
/// <returns>less than zero if strA is less than strB, equal to zero if
/// strA equals strB, and greater than zero if strA is greater than strB</returns>
public static int CompareVersions(string strA, string strB)
{
char[] splitTokens = new char[] {'.', ','};
string[] strAsplit = strA.Split(splitTokens, StringSplitOptions.RemoveEmptyEntries);
string[] strBsplit = strB.Split(splitTokens, StringSplitOptions.RemoveEmptyEntries);
int[] versionA = new int[4];
int[] versionB = new int[4];
for (int i = 0; i < 4; i++)
{
versionA[i] = Convert.ToInt32(strAsplit[i]);
versionB[i] = Convert.ToInt32(strBsplit[i]);
}
// now that we have parsed the input strings, compare them
return RecursiveCompareArrays(versionA, versionB, 0);
}
/// <summary>
/// Recursive function for comparing arrays, 0-index is highest priority
/// </summary>
private static int RecursiveCompareArrays(int[] versionA, int[] versionB, int idx)
{
if (versionA[idx] < versionB[idx])
return -1;
else if (versionA[idx] > versionB[idx])
return 1;
else
{
Debug.Assert(versionA[idx] == versionB[idx]);
if (idx == versionA.Length - 1)
return 0;
else
return RecursiveCompareArrays(versionA, versionB, idx + 1);
}
}
@ Darren Kopp:
版本类不处理1.0.0.5格式的版本。
答案 0 :(得分:39)
使用Version类。
Version a = new Version("1.0.0.0");
Version b = new Version("2.0.0.0");
Console.WriteLine(string.Format("Newer: {0}", (a > b) ? "a" : "b"));
// prints b
答案 1 :(得分:31)
System.Version类不支持带逗号的版本,因此Darren Kopp提供的解决方案是不够的。
这是一个尽可能简单的版本(但并不简单)。
它使用System.Version但通过在比较之前进行搜索替换来实现与“1,2,3,4”等版本号的兼容性。
/// <summary>
/// Compare versions of form "1,2,3,4" or "1.2.3.4". Throws FormatException
/// in case of invalid version.
/// </summary>
/// <param name="strA">the first version</param>
/// <param name="strB">the second version</param>
/// <returns>less than zero if strA is less than strB, equal to zero if
/// strA equals strB, and greater than zero if strA is greater than strB</returns>
public static int CompareVersions(String strA, String strB)
{
Version vA = new Version(strA.Replace(",", "."));
Version vB = new Version(strB.Replace(",", "."));
return vA.CompareTo(vB);
}
代码已经过测试:
static void Main(string[] args)
{
Test("1.0.0.0", "1.0.0.1", -1);
Test("1.0.0.1", "1.0.0.0", 1);
Test("1.0.0.0", "1.0.0.0", 0);
Test("1, 0.0.0", "1.0.0.0", 0);
Test("9, 5, 1, 44", "3.4.5.6", 1);
Test("1, 5, 1, 44", "3.4.5.6", -1);
Test("6,5,4,3", "6.5.4.3", 0);
try
{
CompareVersions("2, 3, 4 - 4", "1,2,3,4");
Console.WriteLine("Exception should have been thrown");
}
catch (FormatException e)
{
Console.WriteLine("Got exception as expected.");
}
Console.ReadLine();
}
private static void Test(string lhs, string rhs, int expected)
{
int result = CompareVersions(lhs, rhs);
Console.WriteLine("Test(\"" + lhs + "\", \"" + rhs + "\", " + expected +
(result.Equals(expected) ? " succeeded." : " failed."));
}
答案 2 :(得分:1)
好吧,既然你只有一个四元素数组,你可能只想展开递归以节省时间。将数组作为参数传递将占用内存并为GC稍后清理留下一团糟。
答案 3 :(得分:0)
如果你可以假设版本字符串中的每个地方只有一个数字(或者至少是最后一个数字,你可以删除逗号或句号并比较......这会快得多......不是虽然很强大,但你并不总是需要它。
public static int CompareVersions(string strA, string strB)
{
char[] splitTokens = new char[] {'.', ','};
string[] strAsplit = strA.Split(splitTokens, StringSplitOptions.RemoveEmptyEntries);
string[] strBsplit = strB.Split(splitTokens, StringSplitOptions.RemoveEmptyEntries);
int versionA = 0;
int versionB = 0;
string vA = string.Empty;
string vB = string.Empty;
for (int i = 0; i < 4; i++)
{
vA += strAsplit[i];
vB += strBsplit[i];
versionA[i] = Convert.ToInt32(strAsplit[i]);
versionB[i] = Convert.ToInt32(strBsplit[i]);
}
versionA = Convert.ToInt32(vA);
versionB = Convert.ToInt32(vB);
if(vA > vB)
return 1;
else if(vA < vB)
return -1;
else
return 0; //they are equal
}
是的,我也假设这里有4个版本的地方......