Question

我有两个数组：

$a = array (

[0] => 0
[1] => 1
[2] => 2
[3] => 3

)

$b = array (

[0] => 2
[1] => 1
[2] => 3
[3] => 4

)

如果我想计算同一个对象，我可以使用array_intersect - ＆gt; echo count(array_intersect($a,$b));。哪个返回：3

但是，我想排除它们相同的行：

$a = array (

[0] => 0
[1] => 1 //Both are the same that I would like to exclude
[2] => 2
[3] => 3

)

$b = array (

[0] => 2
[1] => 1 //Both are the same that I would like to exclude
[2] => 3
[3] => 4

)

只返回2。

我该怎么做？感谢

Answer 1

试试这个

$a = array (0,1,2,3);
$b = array (2,1,3,4);

$final = array_unique(array_merge($a,$b));

print "total : ". count($final);

Answer 2

我会使用一个循环，现在不能想到其他任何东西。

void print_list(void)
{
    atom *element;

    element = &indeks.head->next;

    while (element != &indeks.head) {
        // print whatever info
        element = element->next;
    }
}

PHP Comapring Array包含相同的字符串，不包括相同的行

2 个答案: