Question

我已经写了一个作业，试着计算一个字符串中每种元音的数字。

它编译得很好，但似乎在循环语句中循环，我无法看到我做错了什么，尽管大约一个小时的谷歌搜索。

请帮忙！ =]

 import java.util.Scanner;

 public class assignment3b
 {
public static void main(String[] args)
{
    int alpha=0, epsilon=0, india=0, oscar=0, uniform=0, position=0, length;

    String input;

    char letter;

    Scanner scan = new Scanner(System.in);

    System.out.println("Welcome to the vowel parse-o-matic");
    System.out.println("\nThis program will count all lower case vowels in whatever you type.");
    System.out.print("\nPlease enter the word you'd like to have parsed : ");

        input = scan.next();

        System.out.println("\n\nThe word " + input + " has: "); // reprints the word before stripping spaces

        input = input.replaceAll("\\s+","");                // Removes whitespace so they don't get counted.

    while (position < input.length());
    {
        letter = input.charAt(position);

        switch (letter)
        {
            case 'a':
                alpha = alpha + 1;
                position = position +1;
                break;
            case 'e':
                epsilon = epsilon + 1;
                position = position +1;
                break;
            case 'i':
                india = india + 1;
                position = position +1;
                break;
            case 'o':
                oscar = oscar + 1;
                position = position +1;
                break;
            case 'u':
                uniform = uniform + 1;
                position = position +1;
                break;
            default:
                position++;
                break;  
        }

        System.out.println("a's = " + alpha);
        System.out.println("e's = " + epsilon);
        System.out.println("i's = " + india);
        System.out.println("o's = " + oscar);
        System.out.println("u's = " + uniform);
        System.out.println("\nOther characters = " + (input.length() - alpha -epsilon - india -oscar - uniform));
    }
}

}

Answer 1

删除分号

while (position < input.length());
                                 ^

阻止position递增

Answer 2

import java.util.Scanner;

    public class assignment3b
    {
        public static void main(String[] args)
        {
            int alpha = 0, epsilon = 0, india = 0, oscar = 0, uniform = 0, position = 0, length;

            String input;

            char letter;

            Scanner scan = new Scanner(System.in);

            System.out.println("Welcome to the vowel parse-o-matic");
            System.out.println("\nThis program will count all lower case vowels in whatever you type.");
            System.out.print("\nPlease enter the word you'd like to have parsed : ");

            input = scan.next();

            System.out.println("\n\nThe word " + input + " has: "); // reprints the word before
                                                                    // stripping spaces

            input = input.replaceAll("\\s+", ""); // Removes whitespace so they don't get counted.
            int len = input.length();

            while (position < len)

            {
                letter = input.charAt(position);

                switch (letter)
                {
                    case 'a':
                        alpha = alpha + 1;
                        position = position + 1;
                        break;
                    case 'e':
                        epsilon = epsilon + 1;
                        position = position + 1;
                        break;
                    case 'i':
                        india = india + 1;
                        position = position + 1;
                        break;
                    case 'o':
                        oscar = oscar + 1;
                        position = position + 1;
                        break;
                    case 'u':
                        uniform = uniform + 1;
                        position = position + 1;
                        break;
                    default:
                        position++;
                        break;
                }
            }
                System.out.println("a's = " + alpha);
                System.out.println("e's = " + epsilon);
                System.out.println("i's = " + india);
                System.out.println("o's = " + oscar);
                System.out.println("u's = " + uniform);
                System.out.println("\nOther characters = "
                        + (input.length() - alpha - epsilon - india - oscar - uniform));

        }
    }

试试这个。

正如其他人所提到的，你有一个它不属于的分号。而且我还纠正了你的逻辑并将print语句移到了循环之外。

希望这是你期望的最终结果

Welcome to the vowel parse-o-matic

This program will count all lower case vowels in whatever you type.

Please enter the word you'd like to have parsed : striker


The word striker has: 
a's = 0
e's = 1
i's = 1
o's = 0
u's = 0

Other characters = 5

Answer 3

你有一个不属于它的额外半冒号。

while (position < input.length());

此分号不是语法错误。它描述了一个带有空循环内容的while块。它转换为：

while (position < input.length()) {}

所以，放下分号，你们都很好。

卡在开关回路中

3 个答案: