令牌上的语法错误＆＃34; start＆＃34;，此令牌后预期的标识符

Question

此代码不起作用，如何摆脱启动错误

Thread enemySpawner = new Thread(new Runnable() {
        public void run() {

            for (Slender p : enemies) {
                p.spawnEnemy(g);
                try {
                    Thread.sleep(5000);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }
    });
    enemySpawner.start();

Answer 1

发表声明

select salary from table order by salary desc limit 1,1

在代码块中，例如方法而不是类块