Question

以下代码出了什么问题？

$cores = array ("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF");
foreach ($cores as $cor)
{
    echo "<tr>";
    echo "<td bgcolor = $cor></td>";
    echo "</tr>";
}

但是这段代码有效：

$cores = array ("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF");

for ($i=0; $i<7; $i++)
{
    echo "<tr>";
    echo "<td bgcolor=$cores[$i]></td>";
    echo "</tr>";
}

此外，它不是在列中给出颜色（这是目标），而是在行中。

Answer 1

您在变量周围缺少引号：

foreach ($cores as $cor)
{
    echo "<tr>";
    echo "<td bgcolor = '$cor'></td>";       
    echo "</tr>";
}

Answer 2

这样做：

$colors = array("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF");
$color = $colors[array_rand($colors)];

并将$color变量传递给td

中的bgcolor

echo "<tr>";
echo "<td bgcolor = '$color'></td>";
echo "</tr>";

它将随机拾取颜色。

Answer 3

如果您的目标是列，请使用：

<?php
    $cores = array ("#FF0000","#FFBF00","#FFFF00","#04B404","#58FAF4","#0101DF");
    echo "<table>";
    echo "<tr>";
    foreach ($cores as $cor)
    {
        echo "<td bgcolor= \"$cor\">1</td>";
    }
    echo "</tr>";
    echo "</table>";
?>

使用PHP数组脚本在HTML中交替列颜色

3 个答案: