Question

这是我的产品型号：

$this->table('products');
$this->belongsTo('OrderProducts', [
    'foreignKey' => 'order_product_id',
    'propertyName' => 'order_product',
    'joinType' => 'INNER'
]);
$this->hasMany('RefundProducts', [
    'foreignKey' => 'product_id',
    'sort' => ['RefundProducts.created' => 'DESC'],
    'propertyName' => 'refund_products',
    'className' => 'RefundProducts'
]);

我的查询：

$result = $this->Products->find('all', [
    'contain' => [
        'RefundProducts' => [
            'PriceUnits',
            'conditions' => $refund_condition,
        ]
    ]
]);

但它获得了所有产品，我想只得到产品有RefundProducts

Answer 1

CaoThếCường，您是否尝试过像这样的关系查询：

$result = Products->find()->contain(['RefundProducts' => function ($q) {
   return $q
        ->select(['field1', 'field2'])
        ->where(['refunded_product' => true])]);

Answer 2

这是 matching() 方法的工作，它将使用RefundProducts创建INNER JOIN，因此您只能获得 Products 有一些 RefundProducts。 contain中的条件仅限制获取的关联

 $result = $this->Products->find()
    ->contain(['RefundProducts' => function ($q) use ($refund_condition) {
        return $q->where($refund_condition);
    }])
    ->matching('RefundProducts')
    ->distinct(['Products.id']);

我不确定$refund_condition应该做什么。此示例将Products得到RefundProducts，但只有在RefundProducts满足时才会包含$refund_condition（因此RefundProducts可以返回为空）。或者，根据您要过滤的内容，您可以这样做

->contain(['RefundProducts'])
->matching('RefundProducts', function ($q) use ($refund_condition) {
    return $q->where($refund_condition);
})

Answer 3

使用where检查是否使用了相关表格（在这种情况下为RefundProducts）的列：

// in your query-object
$query->where(['Table.column IS NOT NULL']);

Cakephp3查询模型

3 个答案: