Question

我有一个用户可以定义产品的设置（例如＆＃39; MacBook Pro＆＃39;）。每个Product获得＆＃34;实例化＆＃34;创建一个获取序列号的物理项（ProductInstance）。到目前为止非常简单。

我希望用户能够定义其他类型的唯一标识符，例如MAC地址，VIN，社会安全号码等。我称之为UIDType。每个产品可以包含零个或多个UIDType。这些需要通过分配名称/描述并链接到Product和UIDType（UIDProductInfo）来以某种方式区分。要实际分配值，我需要为特定UIDProductInfo的{{1}}分配值 - 这是使用ProductInstance模型完成的。

当用户实例化产品（创建UID）时，他们应该被迫为ProductInstance UID的每个UIDProductInfo创建一个Product个＆＃ 39;重新实例化。我想在一个页面上完成所有操作。这是一个问题：使用CreateView，我该怎么做？

我认为我需要ModelForm ProductInstance和一个处理UID的formset。 UID formset中的表单需要创建一个UID，该UIDProductInfo绑定到与Product关联的每个ProductInstance对象以及新创建的initial 1}}。不幸的是，我不知道该怎么做。我在CreateView get_context_data方法中创建表单集时尝试使用CreateView.get_context_data参数，还有一些其他更常用的方法，但我无法获得formset正确创建。

感谢您的帮助。模型和我对# a product, i.e. Toyota Corolla class Product(models.Model): name = models.CharField(max_length = 255) identifiers = models.ManyToManyField('UIDType', related_name = 'products', through = 'UIDProductInfo') # a physical item, an "instantiation" of a Product. Gets a serial number class ProductInstance(models.Model): serial_number = models.CharField(max_length = 255) product = models.ForeignKey(Product, related_name = 'instances') # a type of unique identifier, like a MAC address class UIDType(models.Model): name = models.CharField(max_length = 255, unique = True) # a description of a UIDType as it applies to a particular Product. # for example, a computer might get two MAC addresses, 'Host MAC 1' and 'Host MAC 2' class UIDProductInfo(models.Model): name = models.CharField(max_length = 255) type = models.ForeignKey(UIDType, related_name = 'info') product = models.ForeignKey(Product, related_name = 'product_identifiers') # a unique identifier for a ProductInstance class UID(models.Model): value = models.CharField(max_length = 255) info = models.ForeignKey(UIDProductInfo, related_name = 'values') product_instance = models.ForeignKey(ProductInstance, related_name = 'identifiers')方法的悲伤尝试在

之下

模型：

def get_context_data(self, **kwargs):
    self.object = None
    context = super(ProductInstanceCreate, self).get_context_data(**kwargs)

    product = get_object_or_404(Product, id = self.kwargs.get('product_pk'))

    uid_info = [ ]

    pi = ProductInstance(product = product)

    for info in pi.product.product_identifiers.all():
        uid = UID(productInstance = pi, id_type = info)
        uid_info.append({'info':uid})

    UIDFormset = inlineformset_factory(ProductInstance, UID,
            fields = ('identifier', 'info',), can_delete = False,
            widgets = { 'info' : HiddenInput() },
            labels = {'identifier' : ''}, extra = 3)

    uid_formset = UIDFormset(
            instance = pi,
            initial = uid_info
            )

    context['identifiers_formset'] = uid_formset

    return context

get_context_data：

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8"/>
  <title></title>
  <script>
  window.onload = function() {
     var innerDiv = document.getElementById("innerDiv");
     var newDiv = document.createElement("div");
     for (var i = 0; i < innerDiv.childNodes.length; i++) {
        var anchor = 
           newDiv.appendChild(document.createElement("a"));
        anchor.setAttribute("href", "http://www.bing.ca");
        anchor.text = innerDiv.childNodes[i].textContent;
        newDiv.appendChild(document.createElement("br"));
}
innerDiv.replaceNode(newDiv);
}
</script>
</head>
<body>
   <div id="outerDiv">
      <p class='mainPara'>Main Paragraph</p>
   <ul>
      <li>First List Item</li>
      <li>Second List Item</li>
      <li>Third List Item</li>
      <li>Fourth List Item</li>
   </ul>
   <div id="innerDiv">
      <p class='subPara' id='P1'>Paragraph 1</p>
      <p class='subPara' id='P2'>Paragraph 2</p>
      <p class='subPara' id='P3'>Paragraph 3</p>
      <p class='subPara' id='P4'>Paragraph 4</p>
   </div>
   <table>
   </table>
   <input type="text"/><input type="submit" value="Submit!">
</body>
</html>

Answer 1

我使用此处描述的技术解决了这个问题，而不是使用formset：

https://collingrady.wordpress.com/2008/02/18/editing-multiple-objects-in-django-with-newforms/

使用Django中的CreateView创建复杂的多模型对象

1 个答案: