MYSQL选择多对多

时间:2015-05-26 19:28:12

标签: php mysql pdo many-to-many

我正在使用两个表:comment,user

评论表的收件人字段包含用户ID

现在我们必须将评论/收件人更改为多人关系,因为多个用户可以收到相同的评论,所以我添加了一个链接表,comment_recipient

但是,现在我不确定在选择评论时如何选择收件人列表

我不确定如何根据特定收件人选择评论

这就是我现在所拥有的:

$sql = "SELECT c.*, [RECIPIENTS]
FROM comment AS c
JOIN user AS u2 ON c.sender = u2.id
WHERE c.type<=?";
if(isset($args['location'])) $sql .= " AND u2.location=?";
if(isset($args['userId'])) {
  if(isset($args['given'])) {
    $sql .= " AND c.sender=?";
  }else {
    $sql .= " AND c.recipient=?"; //need to see if in recipient list now?
  }
}

编辑:

感谢Barry的回答,我现在得到了这个:

$sql = "SELECT c.*
FROM comment_recipient AS cr
JOIN comment AS c ON c.id=cr.comment_id
JOIN user AS u2 ON c.sender = u2.id
WHERE c.type<=?";
if(isset($args['location'])) $sql .= " AND u2.location=?";
if(isset($args['userId'])) {
  if(isset($args['given'])) {
    $sql .= " AND c.sender=?";
  }else {
    $sql .= " AND cr.user_id=?";
  }
}
$sql .= " GROUP BY c.id";
$sql .= " ORDER BY c.date DESC";
$sql .= " LIMIT ?";
$sql .= " OFFSET ?";

然后,我将使用第二个查询为每个评论选择收件人

1 个答案:

答案 0 :(得分:1)

假设您有以下表格:

  • 用户(ID,姓名)

  • 评论(ID,姓名)

  • CommentRecipient(User_ID,Comment_ID) - 这两者都是 上表中的外键。

不是那么简单: 当您知道Comment查询链接表时获取收件人:

SELECT User_ID from CommentRecipient where Comment_ID= mycommentid;

反之亦然

SELECT Comment_ID from CommentRecipient where User_ID= myuserid;

很抱歉,如果我误解了这个问题。