在android中解析soap响应而不使用kso​​ap

Question

使用以下

从android am访问wsdl servise

    HttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(BASIC_URL);
    try {
        StringEntity se = new StringEntity(SoapRequest, HTTP.UTF_8);
        se.setChunked(true);

        se.setContentType("text/xml");
        httpPost.addHeader("Accept-Encoding", "gzip,deflate");
        httpPost.addHeader("SOAPAction", SoapAction);
        httpPost.addHeader("Content-Type",   "text/xml;charset=UTF-8");
        httpPost.addHeader(header);
        httpPost.setEntity(se);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity resEntity = httpResponse.getEntity();
       // response = EntityUtils.toString(resEntity);
        return httpResponse;
    } catch (Exception e) {

    }

其中 SoapRequest 是一个肥皂串，得到了服务器的响应，但是如何解析soap响应，因为我没有使用 HttpTransportSE 和 ksoap 我不有一个肥皂对象作为回应。

1. 这是从android访问wsdl servise的正确方法吗？
2. 我可以将soap对象转换为xml或json，然后解析它

样本回复是

 <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org /soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
 <soap:Body>
   <GetResponse xmlns="http://tempuri.org/">
     <GetResult>
        <xs:schema id="NewDataSet" xmlns=""   xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
           <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
              <xs:complexType>
                 <xs:choice minOccurs="0" maxOccurs="unbounded">
                    <xs:element name="First">
                       <xs:complexType>
                          <xs:sequence>
                             <xs:element name="FirstElement" type="xs:int" minOccurs="0"/>
                          </xs:sequence>
                       </xs:complexType>
                    </xs:element>

                 </xs:choice>
              </xs:complexType>
           </xs:element>
        </xs:schema>
           <NewDataSet xmlns="">
              <Exception diffgr:id="Exception1" msdata:rowOrder="0">
                 <ex_id>12</ex_id>
              </Exception>               
              <Second diffgr:id="Second" msdata:rowOrder="0">
                 <SecondElement>66</SecondElement>
              </Second>
           </NewDataSet>
     </GetResult>
  </GetResponse>

Answer 1

我们可以解析Soap响应作为解析xml.Using xmlpull解析器我们可以提取xml标签。认为他们不需要 HttpTransportSE 和 ksoap

ant -Dj2ee.server.home=D:\apache-tomcat-8.0.23 clean

ant -Dj2ee.server.home=D:\apache-tomcat-8.0.23 compile

ant -Dj2ee.server.home=D:\apache-tomcat-8.0.23 dist