我刚才注意到在.size
的查询中使用.count
或joins
会产生意外结果。
User.some_scope.size #=> 10
User.joins(:associations).some_scope.size #=> 10 + associated object count
无论我加入桌面,如何获得符合范围的用户数量?
一些实际代码:
class User < ActiveRecord::Base
has_many :tracking_logs, class_name: "Tracking::Log", dependent: :destroy
end
class Tracking::Log < ActiveRecord::Base
belongs_to :user
end
User.where(created_at: Time.now-1.day..Time.now).size #=> 18
SQL: SELECT COUNT(*) FROM "users" WHERE ("users"."created_at" BETWEEN '2015-05-25 10:40:11.423142' AND '2015-05-26 10:40:11.423741')
User.joins(:tracking_logs).where(created_at: Time.now-1.day..Time.now).size #=> 3188
SQL: SELECT COUNT(*) FROM "users" INNER JOIN "tracking_logs" ON "tracking_logs"."user_id" = "users"."id" WHERE ("users"."created_at" BETWEEN '2015-05-25 10:41:15.260113' AND '2015-05-26 10:41:15.260684')
我希望.size
仅应用于我调用查询的基本模型,其他任何事情都只是令人困惑。
NB ,明确说明要检查哪个模型的created_at不会改变结果,例如
User.joins(:tracking_logs).where( users: { created_at: Time.now-1.day..Time.now } ).size #=> 3188
SQL: SELECT COUNT(*) FROM "users" INNER JOIN "tracking_logs" ON "tracking_logs"."user_id" = "users"."id" WHERE ("users"."created_at" BETWEEN '2015-05-25 10:49:29.485508' AND '2015-05-26 10:49:29.486120')
User attributes:
:id => :integer,
:category => :string,
:email => :string,
:created_at => :datetime,
:updated_at => :datetime,
:locale => :string,
:original_email => :text,
:registration_id => :integer,
:first_name => :text,
:login_count => :integer,
:offer_type => :text,
:cid => :string,
:fb_like_status => :integer,
:product_purchases => :text
Tracking::Log attributes:
:id => :integer,
:user_id => :integer,
:tracking_referer_id => :integer,
:to => :string,
:controller_name => :string,
:action_name => :string,
:tracking_activity_id => :integer,
:time_since_last_log => :integer,
:created_at => :datetime,
:updated_at => :datetime
答案 0 :(得分:0)
此处的问题是,如果用户有多个跟踪日志,则联接将多次返回同一用户。您可以使用uniq仅为每个用户提供一次:
User.joins(:tracking_logs).where(created_at: Time.now-1.day..Time.now).uniq.size
另见:http://guides.rubyonrails.org/active_record_querying.html#joining-a-single-association