Question

我在编程方面有点新意。我希望有人可以帮我解决我的问题。我试图更新我的数据，但这个错误不断出现，我不知道该怎么做。这是我的代码

function updatePromo($name, $imageLocation, $dateRelease, $date){

    if(!isset($this->db))
        return new  Exception("Failed to update promo");

    $sql = "UPDATE  `promo` SET `name` = :name,
            `image_location` = :image_location,
            `date_release` = :date_release,
            `date` = :date WHERE `id` = :id";
    return $this->db->db_insert($sql, array(
            'name'=>$name,
            'image_location'=>$imageLocation,
            'date_release'=>$dateRelease,
            'date'=>$date
    ));

这是更新数据的代码

$db = new PROMO_DAO();

$name = $_POST['updateName'];
$dateRelease = strtotime($_POST['updateDate'])*1000;
$date = $_POST['updateDate'];

$temp_dir = getTempUploadDir();

// mysql inserting a new row
$result = $db->updatePromo($name, $temp_dir, $dateRelease, $date);

// check if row inserted or not
if ($result > 0) {
    $newId = $db->getLastInsertedId($name);

    $temp_target_file = $temp_dir . basename($_FILES["updateImage"]['name']);
    $imageFileType = pathinfo($temp_target_file,PATHINFO_EXTENSION);
    $newfilename = 'promo_' . $newId . '.' . $imageFileType;

    uploadImage($_FILES["updateImage"], $newfilename);

    $db->updateImageLocation($name, '/images/' . $newfilename);

    $response["status"] = 1;
    $response["message"] = "Promo updated successfully.";

} else {
    throw new RuntimeException("Failed to update Promo: " . $name);
}

Answer 1

您缺少一个参数和冒号，将它们添加到插入调用中，如下所示

$sql = "UPDATE  `promo` SET `name` = :name,
            `image_location` = :image_location,
            `date_release` = :date_release,
            `date` = :date WHERE `id` = :id";
    return $this->db->db_insert($sql, array(
            ':name'=>$name,
            ':image_location'=>$imageLocation,
            ':date_release'=>$dateRelease,
            ':date'=>$date,
            ':id'=>$id
    ));

Answer 2

在数组中，您没有在密钥中添加:，也没有在查询的:id子句中使用WHERE参数。

希望这能帮助您解决问题

SQLSTATE [HY093]：更新db中的数据时参数号无效

2 个答案: