Question

我已将按钮标记传递给另一个Viewcontroller。它已经通过，但当我打电话给任何其他方法，如播放音频播放所选按钮时，播放器无法正常工作......

我试过下面的代码：它将按钮的id传递给另一个视图。我在哪里构建播放器并且基于按钮ID我想在其他视图和控制功能上播放一首诗，如音量控制，进度条，持续时间，播放，推送，下一个等... 虽然我正在给一个特定按钮id的方法来播放诗歌，但它不起作用......

这下面的代码在我构建播放器的另一个视图中播放一首诗。 `

- (IBAction)btnpoemclicked:(id)sender {
    btnPressed = [NSString stringWithFormat:@"%li", (long)[sender tag]];

NSLog(@"selected poem -%@",btnPressed);

    PlayerController *pl=[[PlayerController alloc] init];
    pl.btnPressed=btnPressed;
    [pl setBtnPressed:pl.btnPressed];
    [self performSegueWithIdentifier:@"player"  sender:sender];
}

Answer 1

实施按钮操作，例如

- (IBAction)buttonPoemClicked:(id)sender {

    [self performSegueWithIdentifier:@"Player" sender:sender];
}

通过实施prepareForSegue传递你的价值，

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {

    if ([segue.identifier isEqualToString:@"Player"]) {

      PlayerController *playerController = (PlayerController *)segue.destinationViewController;
      playerController.pressedButtonTag = [NSString stringWithFormat:@"%li", (long)[sender tag]];
    }
}

附加说明：尽量使您的变量/类名更容易理解，或尝试遵循Apple建议的命名约定。

Answer 2

使用prepareForSegue时，您应该在Segues中传递值。更新您的代码，如

- (IBAction)btnPoemClicked:(id)sender {
    btnPressed = [NSString stringWithFormat:@"%li", (long)[sender tag]];
    [self performSegueWithIdentifier:@"player"  sender:self];
}

然后在prepareForSegue中将值传递给destinationViewController，就像这样

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if ([segue.identifier isEqualToString:@"player"]) {
        PlayerController *playerController = (PlayerController *)segue.destinationViewController;
        playerController.btnPressed = btnPressed;
    }
}

AVAudioPlayer不在另一个viewcontroller中工作

2 个答案: