Question

问题：

触发器，自动存储在名为“ExcellentSale”的单独表中的销售代理名称，汽车型号和制造商名称，每次商定的价格 SalesTransaction超过汽车要价的20％。（注意：你需要创建实现此触发器之前的'ExcellentSale'表。要创建主键，请使用从1开始并以1）递增的序列。

我正在使用这些表格

Manufacturer(manufacturerID, name, region)

Model(modelNo, name, type, previousModel, manufacturerID)

Car(VIN, dateAcquired, yearBuilt, purchasedPrice, askingPrice,
currentMileage, modelNo)

SalesAgent(agentID, name, DOB)

SalesTransaction(VIN, custID, agentID, dateOfSale, agreedPrice)

这是我的尝试

create sequence generateKey
start with 1
increment by 1;
CREATE TABLE ExcellentSale(
recordNo NUMBER,
agentName VARCHAR2(20) NOT NULL,
modelName VARCHAR2(20) NOT NULL,
manufacturerName VARCHAR2(20) NOT NULL,
PRIMARY KEY(recordNo));
create or replace trigger AutoStore
before insert on SalesTransaction
for each row
declare
SAname varchar2(50);
carModel varchar2(50);
manufacturerName varchar2(50);
askingprice number;
agreedprice number;
begin
select sa.name, mo.name, mu.name, c.askingprice, st.agreedprice
into SAname, CarModel, manufacturerName, askingprice, agreedprice
from manufacturer MU, Model MO, Car C, SalesAgent SA, SalesTransaction ST
where mu.manufacturerid = mo.manufacturerid
and st.vin = c.vin
AND c.vin = :new.vin
AND sa.agentID = :new.agentID;
IF :new.agreedPrice > (1.2 * askingPrice) THEN 
INSERT INTO ExcellentSale
VALUES
(generateKey.nextval, agentName, modelName, manufacturerName);
END IF; 
end AutoStore;
/

我得到的错误是

PL / SQL：ORA -00984：此处不允许使用列

请帮忙，先谢谢你。

Answer 1

在insert语句的VALUES子句中，您可以使用包含所需值的变量而不是列名。

INSERT INTO ExcellentSale
VALUES
(generateKey.nextval, SAname, CarModel, manufacturerName);

oracle触发器：新的上下文变量

问题：

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