反转MongoDB查询结果/反对$和操作

Question

这是我的收藏：

{ _id: "539b6502e9630311ad000033", user: "dummy1", x: 1, y: 1 }

{ _id: "539b64c2bdf763720900003e", user: "", x: 0, y: 1 }

{ _id: "539b653ad2a87581ff00000b", user: "dummy3", x: 1, y: 0 }

{ _id: "cPtudQJyKxffCgaZ9", user: "", x: 2, y: 5 }

{ _id: "Br8tCEwhrhG5tKwdJ", user: "dummy1", x: 1, y: 14 }

{ _id: "9AoLD6nLRnhdRfxPw", user: "dummy1", x: 8, y: 15 }

如何查询包含{x: "1", y: "1"}的<{1}}以外的所有文档？

我正在寻找相反的：

user: "dummy1"

返回：

find({user: "dummy1", "$and": [{x: 1}, {y: 1}]}).limit(10)

我的猜测是：

{_id: "539b6502e9630311ad000033", user: "dummy1", x: 1, y: 1}

返回：未找到任何文件。

Answer 1

要取消布尔AND，您可以使用OR来否定每个术语：

db.test.find({user: 'dummy1', $or: [{x: {$ne: 1}}, {y: {$ne: 1}}]})

哪个输出：

{
    "_id" : "Br8tCEwhrhG5tKwdJ",
    "user" : "dummy1",
    "x" : 1,
    "y" : 14
}
{
    "_id" : "Br8tCEwhrhG5tKwdx",
    "user" : "dummy1",
    "x" : 3,
    "y" : 5
}