Question

这是我的情景：我有一个应用程序，可以下载xml文件并从中提取数据。为此，我创建了一个xml配置文件，如下所示：

<?xml version="1.0" encoding="utf-8" ?>
<labelsSets>
    <labelsSet getUrl="https://www.address.com/services/rest/product-display.xml?expand_entities=0&amp;limit=100000000">
        <fields>
            <field name="item" required="true" xPath="result/item" doGet="false" isRoot="true" />
            <field name="Title" required="true" xPath="title" doGet="false" />
        </fields>
    </labelsSet>
</labelsSets>

“field”节点是我必须从下载的xml中提取的值。所以，我必须将数据插入数据库，并使用EF DbContext Generator生成类似这样的类：

[Table("Winery")]
public partial class Winery
{
    public Winery()
    {
        Wine = new HashSet<Wine>();
    }

    [StringLength(10)]
    public string Id { get; set; }

    [Required]
    [StringLength(200)]
    public string Name { get; set; }

    public DateTime? LastUpdate { get; set; }

    public virtual ICollection<Wine> Wine { get; set; }
}

有没有办法将提取的值从xml映射到db表类？

我想在配置中将“table”和“tableField”属性添加到“field”节点，但是我找不到实现提取值和db类之间映射的方法。

Answer 1

试试这个

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Serialization;
using System.IO;
using System.Data;



namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            //alternate method
            //DataSet ds = new DataSet();
            //ds.ReadXml(FILENAME);

            XmlSerializer xs = new XmlSerializer(typeof(LabelsSets));
            XmlTextReader reader = new XmlTextReader(FILENAME);
            LabelsSets labelSets = (LabelsSets)xs.Deserialize(reader);


        }
    }

}
[XmlRoot("labelsSets")]
public class LabelsSets
{
    [XmlElement("labelsSet")]
    public List<LabelsSet> labelSet {get;set;}
}

[XmlRoot("labelsSet")]
public class LabelsSet
{
    [XmlAttribute("getUrl")]
    public string getUrl {get;set;}
    [XmlElement("fields")]
    public Fields fields {get;set;}
}
[XmlRoot("fields")]
public class Fields
{
    [XmlElement("field")]
    public List<Field> fields {get;set;}
}
[XmlRoot("field")]
public class Field
{
    [XmlAttribute("name")]
    public string name {get;set;}
    [XmlAttribute("required")]
    public Boolean required {get;set;}
    [XmlAttribute("xPath")]
    public string xPath {get;set;}
    [XmlAttribute("doGet")]
    public Boolean doGet {get;set;}
    [XmlAttribute("isRoot")]
    public Boolean isRoot {get;set;}
}

动态地将值映射到类属性

1 个答案: