Question

我希望能够通过我的搜索引擎获得一些帮助，我正在努力写作到目前为止，我有两个.php个文件，一个是index.php，另一个是search.php。 index.php是一个前端网站，用户输入他们想要搜索的内容，搜索结果应该显示在哪里。但是，我认为我的代码不起作用，并且在尝试执行搜索时，我在搜索栏下面编写了很多代码。

以下是代码：的index.php

<!DOCTYPE html PUBLIC "-//W3C??DTD XHTML 1.0 Transitional//EN" http://www.w3.org/TR/xxhtmll/DTD/xhtmll-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml">
<html>
<head>
    <meta http-eqiv="Content-Type" content="text/html; charset=utf-8" />
    <title> Trial Report Database - Home</title>
</head>
<body>
    <center>
    <h2>CIS TDU Trial Report</h2>
    <form action='./search.php' method='get'>
    <input type='text' name='k' size='100' />
    <input type='submit' value='Search'>
    </form>
    </center>
</body>
</html>

和search.php

 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" http://www.w3.org/TR/xxhtmll/DTD/xhtmll-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml">
<html>
<head>
    <meta http-eqiv="Content-Type" content="text/html; charset=utf-8" />
    <title> Trial Report Database - Search</title>
</head>
<body>

    <center>
    <h2>CIS TDU Trial Report</h2>

    <form action='./search.php' method='get'>
        <input type='text' name='k' size='100' placeholder='Enter Trial Here...' />
        <input type='submit' value='Search' /> 
    </form>
    </center>

    <hr />
    <?php
        $k = $_GET['k'];
        $terms = explode("", $k);
        $query = "SELECT * FROM cistdutrd WHERE keywords='$term1'" 

        foreach ($terms as $each){
            $i++;

            if ($i == 1)            
                $query .= "keywords LIKE '%$each%'";
            else 
                $query .= "OR keywords LIKE '%$each%'";
    }

    echo $query

    //collect
    mysql_connect("localhost", "root", "password");
    mysql_select_db("cistdutrd");

    $query = mysql_query($query);
    $numrows = mysql_num_rows($query);

    if ($numrows > 0) {
        while ($row = mysql_fetch_assoc($query)) {
            $id = $row['id'];
            $TName = $row['Trial Name'];
            $TType = $row['Trial Type'];
            $TTeam = $row['Trial Team'];
            $Date = $row['Date'];
            $RHyperlink = $row['Report Hyperlink'];

            echo "<h2><a href='$link'>$TName<a/></h2>
            $TType<br /><br />";
        }

    }
    else

    echo "No results found for \"<b>$k</b>\"";

    //disconnect
    mysql_close ();

    ?>

</body>
</html>

任何帮助，为什么这不起作用。这将不胜感激。非常感谢添

搜索引擎代码错误

0 个答案: