Question

如何删除datagrid中的行。我正在使用以下代码并且它不起作用（前两行正在工作，第三行不起作用）我如何更改代码。

put the dgHilitedLines of group "DGP"  into theLine
   answer theLine
   DeleteLine theLine

Answer 1

如果在datagrid外部执行此操作，则需要使用Dispatch命令删除DataGrid中的行。例如。使用数据网格外的按钮。

on mouseUp
   put the dgHilitedLines of group "DGP"  into theLine
   answer "The selected line var is : " & theLine
   dispatch "deleteline" to group "DGP" with theLine  
   put the result into tDeleteresult
   if tDeleteresult is not empty 
   then 
      answer "There has been a problem deleting the line with message: "&tDeleteresult
   else
      answer "Line Deleted"
   end if
end mouseUp

Answer 2

您是否尝试使用索引而不是行？

put the dgHilitedIndex of me into theIndex 
DeleteIndex theIndex

该行始终是当前的显示顺序，例如

A = 1

B = 2

C = 3

因此，如果你删除第2行，下一行C将成为第2行。这通常是一个问题。

删除行后：

A = 1

C = 2

另一方面，索引在填充数据网格时分配，并且对于一行保持相同，无论您如何排序。这样，您始终可以识别该行

使用索引：

A = 1

B = 2

C = 3

删除第2行后：

A = 1

C = 3

Answer 3

作为一种惯例，我总是明确地做这类事情。 LC本身内的工具和分析比DG本身更容易获得和强大。

总的来说：

  get the dgData of group "yourDG"
  delete line whatever of it
  set the dgData of group "yourDG" to it

克雷格纽曼

Answer 4

与Mr.CoolLion一样的答案更为简洁：

put the dgHilitedLines of group "DataGrid" into theLineNo
dispatch "deleteline" to group "DataGrid" with  theLineNo

如何删除datagrid

4 个答案: