Question

我希望使用变量名$ newmass（常量数字）下的新值添加列mass_reach中数据库中的当前值。我在下面创建了一个双桶循环来提取当前值，然后添加它并在第二个循环中更新值，但似乎无法实现此目的。

if(isset($_POST['mass_reach'])){
   $massreach = $_POST['mass_reach'];

      foreach ($massreach as $massreach_id) {
        $query4  = "SELECT mass_reach FROM coaches WHERE id='{$massreach_id}'";       
        $result4 = mysqli_query($con, $query4);
        $query2  = "UPDATE coaches SET mass_reach='{$newmass}'+'{$result4}' WHERE id='{$massreach_id}'";          
        $result = mysqli_query($con, $query2);
        }
}

我收到错误：我收到错误：可捕获的致命错误： mysqli_result类的对象无法在行中转换为字符串 8即

$query2 = "UPDATE coaches SET mass_reach='{$mass}'+'{$result4}' WHERE id='{$massreach_id}'";

Answer 1

function get_string_between($string, $start, $end){
 $string = " ".$string;
 $ini = strpos($string,$start);
 if ($ini == 0) return "";
 $ini += strlen($start);    
 $len = strpos($string,$end,$ini) - $ini;
 return substr($string,$ini,$len);}

 foreach ($mass_reach as $string) {

     $c_id = get_string_between($string,"[","]");
     $c_mass = get_string_between($string,"(",")");
     $query2  = "UPDATE coaches SET mass_reach='{$mass}' + '{$c_mass}' WHERE id='{$c_id}'";       
     $result2 = mysqli_query($con, $query2);
 }

添加到mySQL数据库中的内容

1 个答案: