Question

我的客户端向服务器发送两个c字符串，只有一个接收到第二个recv（）只是挂起，我必须从我的程序中CTRL-C。

如何才能收到这两封邮件？这是我遇到麻烦的地区。

<?php

$file = 'video360p.mp4';
$fp = @fopen($file, 'rb');

$size   = filesize($file); // File size
$length = $size;           // Content length
$start  = 0;               // Start byte
$end    = $size - 1;       // End byte

header('Content-type: video/mp4');
//header("Accept-Ranges: 0-$length");
header("Accept-Ranges: bytes");
if (isset($_SERVER['HTTP_RANGE'])) {

$c_start = $start;
$c_end   = $end;

list(, $range) = explode('=', $_SERVER['HTTP_RANGE'], 2);
if (strpos($range, ',') !== false) {
    header('HTTP/1.1 416 Requested Range Not Satisfiable');
    header("Content-Range: bytes $start-$end/$size");
    exit;
}
if ($range == '-') {
    $c_start = $size - substr($range, 1);
}else{
    $range  = explode('-', $range);
    $c_start = $range[0];
    $c_end   = (isset($range[1]) && is_numeric($range[1])) ? $range[1] : $size;
}
$c_end = ($c_end > $end) ? $end : $c_end;
if ($c_start > $c_end || $c_start > $size - 1 || $c_end >= $size) {
    header('HTTP/1.1 416 Requested Range Not Satisfiable');
    header("Content-Range: bytes $start-$end/$size");
    exit;
}
$start  = $c_start;
$end    = $c_end;
$length = $end - $start + 1;
fseek($fp, $start);
header('HTTP/1.1 206 Partial Content');
}
header("Content-Range: bytes $start-$end/$size");
header("Content-Length: ".$length);

$buffer = 1024 * 8;
while(!feof($fp) && ($p = ftell($fp)) <= $end) {

if ($p + $buffer > $end) {
    $buffer = $end - $p + 1;
}
set_time_limit(0);
echo fread($fp, $buffer);
flush();
}

fclose($fp);
exit();
?>

第二个recv（）挂起

0 个答案: