Question

I want to retrieve a total for the same column but where each alias contains a different string? How do I do this, my sub query below fails.

SELECT status (
    SELECT COUNT(status) FROM `table`
    WHERE `status` LIKE LOWER('%stage 1%')
    ) AS Stage1,
status (
    SELECT COUNT(status) FROM `table`
    WHERE `status` LIKE LOWER('%stage 1%')
    ) AS Stage2,
status (
    SELECT COUNT(status) FROM `table`
    WHERE `status` LIKE LOWER('%stage 1%')
    ) AS Stage3
FROM `table`

Answer 1

如果您想要三列，请使用条件聚合。这在MySQL中特别容易：

select sum(status LIKE LOWER('%stage 1%')) as status1,
       sum(status LIKE LOWER('%stage 2%')) as status2,
       sum(status LIKE LOWER('%stage 3%')) as status3
from `table`;

Answer 2

Count the result of a CASE statement that aggregates your groups. Here's a fiddle.

SELECT
  CASE
  WHEN status LIKE '%stage 1%' THEN 'stage 1'
  WHEN status LIKE '%stage 2%' THEN 'stage 2'
  WHEN status LIKE '%stage 3%' THEN 'stage 3'
  END as status_group,
  COUNT(*)
FROM statuses
GROUP BY status_group

Get totals for the same column but where each SELECT alias contains a specific string

2 个答案: