Question

 NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
 [dateFormat setDateFormat:@"dd/MM/yyyy"];
 NSString *theDate = [dateFormat stringFromDate:date];
 time_t unixTime = (time_t) [date timeIntervalSince1970];

我需要没有小时，分钟和秒的unixTime

Answer 1

您可能希望从原始日期中提取重要日期组件

NSDate *date = [NSDate date];

NSCalendar *gregorianCalendar = [NSCalendar calendarWithIdentifier:NSCalendarIdentifierGregorian];

NSDateComponents *componentsDate = [gregorianCalendar components:NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay fromDate:date];

然后，与他们建立一个新约会

NSDateComponents *toDateComponents = [NSDateComponents new];
[toDateComponents setYear:[componentsDate year]];
[toDateComponents setMonth:[componentsDate month]];
[toDateComponents setDay:[componentsDate day]];
[toDateComponents setTimeZone:[NSTimeZone timeZoneWithName:@"UTC"]];

NSDate *toDate = [gregorianCalendar dateFromComponents:toDateComponents];

最后，获取时间间隔

NSTimeInterval toDateTimeInterval = [toDate timeIntervalSince1970];

Answer 2

或者从另一个方向来到它，并在Swift：

// Get the current date and time
let theDate = NSDate()

// Get the current hours, minutes and seconds from "now"
let theCalendar = NSCalendar.currentCalendar()
let theComponents = theCalendar.components(.CalendarUnitHour | .CalendarUnitMinute | .CalendarUnitSecond, fromDate: theDate)

// Construct a new time, the equivalent number of seconds earlier than "now". This is effectively midnight that passed
let theCorrectedDate = NSDate( timeInterval: -(NSTimeInterval)((theComponents.hour * 3600) + (theComponents.minute * 60) + theComponents.second), sinceDate: theDate )

// And that gives you the unix time you want
let theUnixTime = theCorrectedDate.timeIntervalSince1970

iOS获取时间戳，无需小时，分钟和秒

2 个答案: