Question

我是法国人，对我糟糕的英语很抱歉，我正在尝试为phoegap做一个测验

我有一个工作的ajax_actions.php

<?php
require('./PDOsql.class.php');
require('./Country.class.php');
require('./Question.class.php');
require('./Answer.class.php');


header('Access-Control-Allow-Origin: *');

if(isset($_POST["actionname"])&&!empty($_POST['actionname'])){
$actionname = $_POST['actionname'];

if($actionname=='getQuestion'){
$name = $_POST['name'];
$c = new Country();
$c->getIdByName($name);
$CountryId = $c->getId();

$q = new Question();
$a = new Answer();

$allQuestion = array();
$allQuestion = $q->getQuestionByCountryId($CountryId);

$allAnswer = array();
foreach ($allQuestion as $question) {
  $allAnswer[] = array(
    $a->getAnswerByQuestionId($question['id'])
  );
}

die(
  json_encode(
    array(
      'state'=>'success','allQuestion'=>$allQuestion,'allAnswer'=>$allAnswer
    )
  )
);
  }
}

我有两节课：问题：

<?php


class Question {

private $id="";
private $text="";
private $connect;

public function getId()
{
    return $this->id;
}

public function setId($id)
{
    $this->id = $id;
    return $this;
}

public function getText()
{
    return $this->text;
}

public function setText($text)
{
    $this->text = $text;
    return $this;
}

public function getQuestionByCountryId($CountryId){
    $this->connect = new PDOsql();
    $sql='SELECT * FROM Question WHERE countryId = ? ORDER BY RAND() LIMIT     5';
    $opt = $CountryId;

    $value =  $this->connect->query($sql,$opt);
    $A_Question = array();
    while($question = $value->fetch()){
        $A_Question[] = array(
            'id'=>$question['id'],
            'text'=>$question['text']
        );
    }
    $this->connect = null;
    return $A_Question;
}
}

我有一个答案课：

<?php


class Answer {

private $id="";
private $text="";
private $isGood="";
private $connect;

public function getId()
{
    return $this->id;
}

public function setId($id)
{
    $this->id = $id;
    return $this;
}

public function getText()
{
    return $this->text;
}

public function setText($text)
{
    $this->text = $text;
    return $this;
}

public function getIsGood()
{
    return $this->isGood;
}

public function setIsGood($isGood)
{
    $this->isGood = $isGood;
    return $this;
}


public function getAnswerByQuestionId($QuestionId){
    $this->connect = new PDOsql();
    $sql='SELECT * FROM Answer WHERE QuestionId = ?';
    $opt = $QuestionId;

    $value =  $this->connect->query($sql,$opt);
    $A_Answer = array();
    while($answer = $value->fetch()){
        $A_Answer[] = array(
            'id'=>$answer['id'],
            'text'=>$answer['text'],
            'isGood'=>$answer['isGood']
        );
    }
    $this->connect = null;
    return $A_Answer;
}
}

点击时点击js函数：

    function getQuestion(name){
    $.ajax({
        type: "POST",
        url: url,     
        dataType: "json",
        data : {
            actionname : 'getQuestion',
            name:name
        },
        success: function(data) {
            allQuestion = data.allQuestion;
            allAnswer = data.allAnswer;
            for (var i = allQuestion.length - 1; i >= 0; i--) {
                alert(allQuestion[i]["text"]);
                for (var j = 0; j < 4 ; j++) {
                    alert("answer "+j+" "+allAnswer[i][j]["text"]); //HERE THAT DOESNT WORKS !
                };
            };
        },
        error: function(data) {
            alert("error !");
        }
    });
}

问题是，我不能得到我的答案清单：/ 谢谢你的帮助

Answer 1

ajax中的A（异步JavaScript + XML）用于异步。这意味着，当ajax请求被触发时，不知道完成所需的时间。因此，在这种情况下，您无法确保订单。

什么是顺序是循环将迭代并触发多个ajax请求。但是，在每次迭代之间，很可能（尽管可能）请求将完成并触发成功处理程序。同样，异步编程不顺序编程。

请参阅Asynchronous vs synchronous execution, what does it really mean?

Answer 2

好的，所以我没有选择我需要把我的ajax 2放在我的ajax 1中：/

foreach ajax不是很好

2 个答案: