Question

<?php
class foo
{
    //this class is always etended, and has some other methods that do utility work
    //and are never overrided
    public function init()
    {
        //what do to here to call bar->doSomething or baz->doSomething 
        //depending on what class is actually instantiated? 
    }

    function doSomething()
    {
        //intentionaly no functionality here
    }


}

class bar extends foo
{
    function doSomething()
    {
        echo "bar";
    }
}

class baz extends foo
{
    function doSomething()
    {
        echo "baz";
    }
}
?>

Answer 1

你只需要拨打$ this-＆gt; doSomething（）;在你的init（）方法中。

由于多态性，将在运行时根据子类的类调用子对象的正确方法。

Answer 2

public function init() {
    $this->doSomething();
}

$obj = new bar();
$obj->doSomething(); // prints "bar"

$obj2 = new baz();
$obj->doSomething(); // prints "baz"

如何在PHP 5中动态调用子类方法？

2 个答案: