Question

我目前在使用对象和类时遇到一些困难。我正在创建对象，在这种情况下，足球运动员在一个类的一个功能中，然后尝试在另一个功能中显示他们的细节。这是创建对象的函数，

void create_all_players(){
Midfielder *midfielder1= new Midfielder("Jordan Lewis");
Midfielder *midfielder2= new Midfielder("David Armitage");
Midfielder *midfielder3= new Midfielder("Tom Rockliff");
Midfielder *midfielder4= new Midfielder("Gary Ablett");
Midfielder *midfielder5= new Midfielder("Dyson Heppel");
Midfielder *midfielder6= new Midfielder("Scott Pendlebury");
Midfielder *midfielder7= new Midfielder("Michael Barlow");
Midfielder *midfielder8= new Midfielder("Jack Steven");
}

这是我试图输出玩家详细信息的功能，

void display_all_players(){

cout<<midfielder1->Player_Details()<<endl;
cout<<midfielder2->Player_Details()<<endl;
cout<<midfielder3->Player_Details()<<endl;
cout<<midfielder4->Player_Details()<<endl;
cout<<midfielder5->Player_Details()<<endl;
cout<<midfielder6->Player_Details()<<endl;
cout<<midfielder7->Player_Details()<<endl;
cout<<midfielder8->Player_Details()<<endl;
}

但是当我尝试运行程序时我得到了错误，'midfielder1'没有在这个范围内声明，对于所有对象。如何在display_all_players函数中没有错误的情况下引用对象？如果需要其他信息，中场是从下面的球员类继承的类。

Player.h

    #ifndef PLAYER_H
    #define PLAYER_H
    #include <string>

    class Player
    {
        public:
            Player();
            Player(std::string);
            std::string Name;
            std::string Get_Name();
            virtual std::string Player_Details();
    };

    #endif // PLAYER_H

Player.cpp

#include "Player.h"
#include <iostream>
#include <string>
#include <sstream>
#include "Player.h"
#include "Midfielder.h"
using namespace std;

Player::Player():Name("Default"){}

Player::Player(string Name){
this->Name=Name;
}


string Player::Player_Details(){

return "Player : " + this->Name ;
}

Midfielder.h

#ifndef MIDFIELDER_H
#define MIDFIELDER_H
#include "Player.h"

class Midfielder : public Player
{
    public:
        Midfielder();
        Midfielder(std::string);
        virtual std::string Player_Details();
};

#endif // MIDFIELDER_H

和Midfielder.cpp

#include <iostream>
#include <string>
#include "Player.h"
#include "Midfielder.h"
using namespace std;

Midfielder::Midfielder(){}

Midfielder::Midfielder(string Name){
this->Name=Name;
}


string Midfielder::Player_Details(){

return "Midfielder : " + this->Name;
}

}

感谢您提前提供任何帮助

Answer 1

您在midfielder方法中创建了create_all_players个变量。这使它们具有功能范围，并且只能从那里访问它们。你需要将中场变量存储在其他地方，比如全局（在任何函数之外）。

错误：'midfielder1'未在此范围内声明

1 个答案: