Question

如何在刷新时更改图像，但是该图像仍有链接？这是我尝试过的：

<SCRIPT LANGUAGE="JavaScript">
var theImages = new Array()

//Random-loading images
theImages[0] = 'image' // replace with names of images
theImages[1] = 'image' // replace with names of images

var j = 0
var p = theImages.length;
var preBuffer = new Array()

for (i = 0; i < p; i++){
preBuffer[i] = new Image()
preBuffer[i].src = theImages[i]
}
var whichImage = Math.round(Math.random()*(p-1));

function showImage(){
    if(whichImage==0){
    document.write('<a href ="link"><img src="'+theImages[0]+'" border=1 width=728 height=90></a>');
    }
    else if(whichImage==1){
    document.write('<a href ="link"><img src="'+theImages[whichImage]+'" border=0 width=728 height=90></a>');
    }
}

</script>
<script>showImage();</script>

我在网上找到了更少的代码，但是一切对我来说都不起作用:(有人可以修复此代码或以其他方式帮助我吗？）

Answer 1

这将在每次运行时随机选择一个图像并相应地设置html img的src属性。

＆＃13;

var images = [
  'image_1.jpg',
  'image_2.jpg',
  'image_3.jpg',
  'image_4.jpg',
  'image_5.jpg'
]

var which = Math.floor(Math.random() * images.length);
var img = document.getElementById('theimage');
img.src = images[which];
img.title = images[which];

＆＃13;

<img id="theimage" />

＆＃13;

刷新时更改图像

1 个答案: