Question

假设我有一个像这样的字符串：

Hey man, my name is Jason and I like Pizza. #Pizza #Name #Cliche

我的问题是如何提取所有以#开头的字符串并将它们放在另一个字符串中？

Answer 1

在regex

上查看本教程

尝试

Matcher matcher = Pattern.compile("(\\s|^)#(\\S*)").matcher(string);
while(matcher.find()){
    System.out.println(matcher.group(2));
}

编辑：

如您还想要其他字符串，您可以尝试

Matcher matcher = Pattern.compile("(\\s|^)#(\\S*)|(\\S+)").matcher(string);

StringJoiner hashfull = new StringJoiner(" ");
StringJoiner hashless = new StringJoiner(" ");

while(matcher.find())
    if(matcher.group(2) != null)
        hashfull.add(matcher.group(2));
    else if(matcher.group(3) != null)
        hashless.add(matcher.group(3));

System.out.println(hashfull);
System.out.println(hashless);

Answer 2

我发现这段代码对我来说非常好用，因为我还想要其余的字符串。感谢@Pshemo和@Mormod帮助我解决这个问题。这是代码：

String string = "Hello my name is Jason and I like pizza. #Me #Pizza";
String[] splitedString = string.split(" "); //splits string at spaces 
StringBuilder newString = new StringBuilder();
StringBuilder newString2 = new StringBuilder();
for(int i = 0; i<splitedString.length; i++){     
if(splitedString[i].startsWith("#")){      
   newString.append(splitedString[i]);
   newString.append(" ");     }
else{     
   newString2.append(splitedString[i]);
   newString2.append(" ");     
    }
 }    
 System.out.println(newString2);     
 System.out.println(newString);

Answer 3

也许你会搜索这样的东西：

String string = "ab cd ef"
String[] splitedString = string.split(" "); //splits string at spaces
String newString = "";
for(int i = 0; i<splitedString; i++){
    if(splitedString[i].startsWith("#")){
        newString += splitedString[i];
    }
}

mormod

从特殊字符选择的大字符串中提取字符串

3 个答案: