Question

我希望能够以某种方式格式化数字，并且对于我调用的每个打印函数都这样，而不是在每个打印函数中重新格式化它。我只是把它看作是一种清理代码的方法。这是一个例子：

鉴于变量：

weight = mass * conversion_const

并说它超过2位小数。

然后我要打印：

print('The mass of the load is %s Newtons, which is too heavy' %(format(weight, ',.2f')))
print('The mass of the load is %s Newtons, which is too light' %(format(weight, ',.2f')))
print('The mass of the load is %s Newtons, which is just right' %(format(weight, ',.2f')))
print('The mass of the load is %s Newtons, which is wayy to heavy' %(format(weight, ',.2f')))

这只是一个例子，如果我要创建需要这些响应的东西，它将在if语句中，但正如您所看到的，无论哪种方式，我都必须每次格式化相同的变量。我怎么能避免这个？

Answer 1

如何提取常见格式代码有很多选项，例如：

ANSWER_FORMAT = 'The mass of the load is {0:,2f} Newtons, which is {1}'
format_answer = ANSWER_FORMAT.format

print(format_answer(right_weight, 'just_right'))
print(format_answer(heavy_weight, 'too heavy'))

（请注意，新格式样式如何让生活更轻松。）

Answer 2

将其格式化一次，将格式化的字符串存储在变量中，然后使用该变量。

Answer 3

weight = "%.2f"%(mass * conversion_const)

print('The mass of the load is %s Newtons, which is too heavy'%(weight))
print('The mass of the load is %s Newtons, which is too light'%(weight))
print('The mass of the load is %s Newtons, which is just right'%(weight))
print('The mass of the load is %s Newtons, which is way to heavy'%(weight))

甚至更好：

weight = "The mass of the load is %.2f Newtons, which is "%(mass * conversion_const)

print(weight + 'too heavy')
print(weight + 'too light')
print(weight + 'just right')
print(weight + 'way too heavy')

如何在python3.x中为多个打印格式化数字？

3 个答案: