Question

我正在使用CakePHP 3.x。

我想要的是能够调用$ this-＆gt; Categories-＆gt; find（），然后加入Topics.cat_id = Categories.id上的主题，然后加入Posts.topic_id = Topics.id上的帖子。< / p>

我没有收到任何错误，但我收到的唯一数据是类别数据，我尝试过LEFT和INNER加入但没有成功。任何帮助将不胜感激。

表关系是：

CategoriesTable

$this->hasMany('Topics');

TopicsTable

$this->belongsTo('Categories');
$this->hasMany('Posts');

PostsTable

$this->belongsTo('Topics');

我也有查询：

$query = $this->Categories->find('all')
        ->order(['Categories.name' => 'ASC'])
        ->join([
            'topics' => [
                'table' => 'Topics',
                'type' => 'LEFT',
                'conditions' => 'topics.Cat_id = Categories.id'
            ],
            'posts' => [
                'table' => 'Posts',
                'type' => 'LEFT',
                'conditions' => 'posts.topic_id = topics.id'
            ]
        ]);

尝试使用可包含的行为，但现在我收到错误＆＃34;类别与帖子＆＃34;使用此查询：

$query = $this->Categories->find('all')
        ->order(['Categories.name' => 'ASC'])
        ->contain(['Topics', 'Posts' => function($q){
            return $q->where(['Posts.topic_id' => 'Topics.id']);
        }]);

Answer 1

With the advice @ndm gave i was able to get the result i wanted. I must have overlooked the section in the docs, so anyone else having this problem, here's how to do it.

$query = $this->Categories->find('all')
        ->order(['Categories.name' => 'ASC'])
        ->contain([
            'Topics.Posts.Users'
        ]);

Answer 2

只要找到cakephp2的遗产，你仍然可以使用旧版本的连接。

$result = $this->Category->findAll(fields=>['id','Topic.id'], 'conditions'=>['Topic.name'=>'s'],'join'=>['Topic' => [
            'table' => 'topics',
            'type' => 'INNER',
            'conditions' => 'Topic.category_id = Category.id'
        ]]);

找到熟悉的？你仍然可以像以前一样使用别名

第一次回答，不确定代码编辑器是如何工作的，抱歉。

Answer 3

试试这个：

 $query = $this->Categories->find('all')
        ->fields('Categories.*', 'Topics.*', 'Posts.*')
        ->order(['Categories.name' => 'ASC'])
        ->join([
            'topics' => [
                'table' => 'Topics',
                'type' => 'LEFT',
                'conditions' => 'topics.Cat_id = Categories.id'
            ],
            'posts' => [
                'table' => 'Posts',
                'type' => 'LEFT',
                'conditions' => 'posts.topic_id = topics.id'
            ]
        ]);

添加以下行：

->fields('Categories.*', 'Topics.*', 'Posts.*')

从主题和帖子中检索数据

如何使用CakePHP 3连接多个表？

3 个答案: