Question

我是红宝石的新手。有没有办法缩短这段代码（＆＃34;增量var＃＆＃34;）？我创建了26个字母表条目。

require 'tk'
dis = { 'padx' =>5, 'pady' =>5}
root = TkRoot.new {title "Alphabet"}
elpar = {'height' => 25, 'width' => 25}
f1 = TkFrame.new{
    relief 'sunken'
    borderwidth 1
    background "black"
    height 800
    width 800
    dis
    pack
    }
f1.place('x' => 0, 'y' => 0)

el00 = TkEntry.new(f1)
el01 = TkEntry.new(f1)
el02 = TkEntry.new(f1)
          to             # Can I use loop here to shorten it?
el26 = TkEntry.new(f1)   


var1 = TkVariable.new
           to            #(1)
var2 = TkVariable.new


el00.textvariable = var1
var1.value = "A"
el00.place(elpar)
el00.place('x' => 0, 'y' => 0)
          to             #
el26.textvariable = var26
var26.value = "Z"
el26.place(elpar)
el26.place('x' => 728, 'y' => 0)

Tk.mainloop

（1）我尝试过使用循环

  x = 1
  while x < 27
    "var#{x}"=TkVariable.new         # var1 is still undefined local variable if I use a loop.  
    "var" + x.to_s=TkVariable.new    # another variation that i've tried 
     x += 1
  end

有没有办法缩短它？我的代码只是1的增量？

谢谢，吉姆

Answer 1

您可以将条目存储在数组中：

entries = Array.new(26) { TkEntry.new(f1) }

然后阅读您的参赛作品：

entries[0] #=> first entry
entries[1] #=> second entry

使用A到Z的字符范围设置参数：

('A'..'Z').each_with_index do |character, index|
  variable = TkVariable.new
  variable.value = character
  entries[index].textvariable = variable 
  entries[index].place(elpar)
  entries[index].place('x' => 0, 'y' => 0)   # you did not explain how to calculate this
end

Ruby的增量变量

1 个答案: