Question

嘿伙计们，我一直在努力，但我无法解决这个问题。请问有人可以帮我吗？我只是困惑，有人可以帮助我如何修复代码？对于内容感到抱歉，因为我无法上传图片。

SELECT Employee.EmpName, Employee.Age

FROM Employee

WHERE Employee.Age < (SELECT COUNT(Employee.EmployeeID)

FROM Employee, Department

WHERE Department.ManagerID = Employee.EmployeeID 

GROUP BY Employee.EmployeeID

HAVING COUNT(Employee.EmployeeID) >= 2)

//（问题）找到管理多个部门的最年轻的经理。查询返回经理的姓名和年龄。

SCHEMA

Employee(EmployeeID:Integer, EmpName: String, Age: Integer, Salary: Real)
Department(DeptID: Integer, DeptName:String, Budget: Real, ManagerID: Integer)
Works(EmployeeID:Integer, DeptID: Integer, Percent_Time: Integer)

Answer 1

试试这个

SELECT e2.EmpName, e2.Age
FROM Employee e2 
JOIN Works w2 USING (EmployeeID)
JOIN (SELECT w.DeptID, MIN(e.Age) AS Youngest
      FROM Works w 
      INNER JOIN Employee e USING (EmployeeID)
      GROUP BY w.DeptID) sq
  ON w2.DeptID = sq.DeptID and e2.Age = sq.Youngest

嵌套查询的SQlite问题

1 个答案: